Regex which will accept alphanumeric with special characters

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Javascript

Regex
which can accept alphanumeric with special characters " A-Za-z0-9()[]+-*/%"

/^[ A-Za-z0-9()[]+-*/%]*$/

Posted 15-Dec-15 0:47am

Member-515487

Updated 30-Dec-20 21:18pm

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OriginalGriff · Accepted Answer · 2015-12-15T00:57:00

Solution 1

Escape the ']' inside the list:

/^[ A-Za-z0-9()[\]+-*/%]*$/

If you are going to use Regular Expressions, get a copy of Expresso[^] - it's free, and it examines and generates Regular expressions.

Posted 15-Dec-15 0:57am

OriginalGriff

Updated 15-Dec-15 0:58am

v3

Comments

Member-515487 15-Dec-15 7:05am

[RegularExpression(@"/^[ A-Za-z0-9()[\]+-*/%]*$/", ErrorMessageResourceType = typeof(ResourceFiles.EntlEngine_Resource), ErrorMessageResourceName = "RuleEditorRegexValidation")]

it not working it giving u run time exception

OriginalGriff 15-Dec-15 7:12am

:sigh:
You can't just put the backslash in as part of a javascript string: backslash is an escape character in JS as well, so you would need two of them to pass one through to the Regex parser...

Member-515487 15-Dec-15 7:11am

parsing "^[ A-Za-z0-9()[\]+-*/%]*$/" - [x-y] range in reverse order.

Member-515487 15-Dec-15 7:39am

@"^[ A-Za-z0-9\[\]()*\-+/%]*$