How to check if all values in a comma separated string values are numeric?

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SQL-Server-2008R2

I want to check if comma separated string

JavaScript

'822632,822633,822634,822635,827402,827403,827404,827405'

have all numeric values??

I tried ISNUMERIC but something feels off

SQL

select ISNUMERIC('822632,822633,822634,822635,827402,827403,827404,827405') -- 0
Select ISNUMERIC('822632,822633') --1
Select ISNUMERIC('8226326125163143146341') --1
Select ISNUMERIC('822632,822633,822') -- 1
Select ISNUMERIC('822632,822633,8243') --0
Select ISNUMERIC('822632323232233,822633') -- 0
Select ISNUMERIC('8226323,8226335612') --0

What are other options and why ISNUMERIC is not working properly

Thanks

Posted 15-Dec-15 21:01pm

Gaurav_Chaudhary

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2 solutions

Solution 1

You could try and replace the comma first and then do ISNUMERIC.
Something like this:

SQL

select ISNUMERIC(replace('8226323,8226335612',',','')) AmINumeric

Not sure if it will work on really really very large numbers though.

Posted 15-Dec-15 22:15pm

jaket-cp

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Andy Lanng · Accepted Answer · 2015-12-15T22:26:00

You can use PATINDEX:

SQL

select PATINDEX('%[^0-9,]%', '822632,822633,822634,822635,827402,827403,827404,827405') -- 0
Select  PATINDEX('%[^0-9,]%', '822632,822633') --0
Select  PATINDEX('%[^0-9,]%', '8226326125163143146341') --0
Select  PATINDEX('%[^0-9,]%', '822632,822633,822') -- 0
Select  PATINDEX('%[^0-9,]%', '822632,822633,8243') --0
Select  PATINDEX('%[^0-9,]%', '822632323232233,822633') -- 0
Select  PATINDEX('%[^0-9,]%', '8226323,8226335612') --0
Select  PATINDEX('%[^0-9,]%', '822632,a822633') --8
Select  PATINDEX('%[^0-9,]%', 'a822632,a822633') --1

The pattern [0-9,] looks for any of 1 to 9 or comma, [^0-9,] looks for everything else. If it finds any other char it will return index>0, otherwise zero