How to pass complete model data to the @Html.ActionLink and get that model into controller action parameter in MVC 4?

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C#

Hi Team,

I have a Model on my View, i want to pass that Model to the @Html.ActionLink, i have tried by some google articles, found not fruitful. Within my model i have two another model for ex. lets consider below is my model structure-

Public class TestModel

{

  public Test1Model test1{get;set;}

public Test2Model test2{get;set;}

}

Now, i want to pass TestModel to the @Html.ActionLink and want to access as a parameter to the action of controller.

Please suggest if someone have a nice approach on his.

Thanks.

Posted 19-Jan-16 17:41pm

Member 8090436

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DreamInHex · Answer 1 · 2016-01-20T09:45:00

You can't, in short.

An ActionLink helper renders as an anchor tag (hyperlink). This link, when clicked, performs a GET against the specified controller action, meaning that you can pass parameters to it via the query string (html attributes object within the helper), but you cannot post the model to your controller via an ActionLink. For example:

HTML

@Html.ActionLink("My Link", "MyControllerAction", new { id = Model.Id })

This would submit a GET request to your controller like so:

C#

public async Task<Actionresult> MyControllerAction(int id)
{
    // Do stuff with the id
}

If you want to post a complete model to a controller, use a form with a submit button. This will submit your model back to the controller. You can style the submit button to look like a link.

Alternatively, use the passed in id property to load the model from a data store.