How to pass 2d arrays and print the employee age, id, and salary

#include <iostream>
#include <cmath>
#include <math.h>
#include <string>

using namespace std;


class Employee {

public:
	Employee();//construct
	void setAge(int x) {
		age = x; 
	};
	int Employee::getAge() {
		return age;
	};

	void setId(int x) {
		id = x;
	};
	int Employee::getId() {
		return id;
	};
	void setSalary(float x) {
		salary = x;
	};
	float Employee::getSalary() {
		return salary;
	};
	void PrintEmployee(Employee arg1[][3], int arg2, int arg3);
private:
	int age; 
	int id; 
	float salary; 

};
Employee::Employee() {
		 age = 0;
		id = 0;
		 salary = 0.0;
};

void Employee::PrintEmployee(Employee arg1[][3], int arg2, int arg3) {

	int totalage = 0; ;
	int  totalsalary = 0;
	float avargeAge = 0; 
	float avargeSalary = 0; 
	    for (int row = 0; row < arg2; row++) {
		for (int colm = 0; colm < arg3; colm++) {

			totalage = totalage + arg1[row][colm].getAge();
			totalsalary = totalsalary + arg1[row][colm].getSalary();
			avargeAge = (totalage / 6);
			avargeSalary= (totalsalary / 6);

		}
	}
	
		cout << " The Average age is " << avargeAge << endl;
		cout << " The Average salary is " << avargeSalary << endl;

}


int main() {


	Employee x[2][3];
	Employee object;



	x[0][0].setAge(30); x[0][0].setId(111); x[0][0].setSalary(30000);
	x[0][1].setAge(31); x[0][1].setId(112); x[0][1].setSalary(31000);
	x[0][2].setAge(32); x[0][2].setId(113); x[0][2].setSalary(32000);
	x[1][0].setAge(33); x[1][0].setId(114); x[1][0].setSalary(33000);
	x[1][1].setAge(34); x[1][1].setId(115); x[1][1].setSalary(34000);
	x[1][2].setAge(35); x[1][2].setId(116); x[1][2].setSalary(35000);

	object.PrintEmployee(x, 2, 3);

	system("pause");
	return 0;
}