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Hi all, i have visual studio 2012 winform c#

Using Mysql, i would like to insert record if not exists already in the table

What I have tried:

INSERT INTO refreshcity (Id, Society) values ('900000','toto')
WHERE NOT EXISTS (Select Id, Society From refreshcity WHERE Id ='900000')
Posted
Updated 13-Jun-19 18:23pm

INSERT INTO `refreshcity` (`Id`, `Society`) 
SELECT '900000','toto'
WHERE NOT EXISTS (Select `Id` From `refreshcity` WHERE `Id` ='900000') LIMIT 1;

This work for me.
 
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if you have an "unique" column you could simply do "insert ignore into... "; it will automatically check the unique column for duplicate an each row that is about to be inserted and will simply ignore an entry if already existing.
 
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Comments
CHill60 15-May-18 7:02am    
"ignore into ..." - As discussed on the link provided in Solution 1 a year ago.
There is slight change in Query, Just try to select the record first which you want to insert in database, if it is not exist then you can insert in it.
see below snippet

SQL
INSERT INTO table_listnames (name, address, tele)
SELECT * FROM (SELECT 'name1', 'add', '022') AS tmp
WHERE NOT EXISTS (
    SELECT name FROM table_listnames WHERE name = 'name1'
) LIMIT 1;


Hope it helps
 
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Comments
koolprasad2003 7-Apr-16 3:46am    
look, I have a table named table_listnames and I want to insert name, address and telephone number in table but before insertion I want to check if the same entry with same name is already exist or not. so first I will select name from table where name is the same name I want to insert. if it is not exist then it will insert new record.
Its for MySQL not for SQL
Armel_Djient 7-Apr-16 3:49am    
i got how this command works.
INSERT INTO table_listnames (name, address, tele)
represents the columns where the data will be inserted
SELECT * FROM (SELECT 'name1', 'add', '022') AS tmp
traduces the values to be inserted in the columns(name, address, tele) mentionned above
WHERE NOT EXISTS
to checks if the record already exists or not

Thank you very much for your reply
koolprasad2003 7-Apr-16 5:11am    
welcome
klmediadev 17-Oct-19 5:54am    
awesome, koolprasadd! thank you for this useful snipp :-) good health!
koolprasad2003 17-Oct-19 6:17am    
glad it helps...
 
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