How to split a string into arrays

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have a input string eg "123456789098765432" need to split into two arrays OddArray and EvenArray based on the positionsi.e, all the digits in even position(2,4,6,8....) to EvenArray and all the digits in oddposition(3,5,7...) to OddArray

What I have tried:

C#

char EvenArray[256],OddArray[256],Inputarray[256];
CString dis = "123456789098765432";
strcpy(Inputarray,dis);
int i,j,k;
int x = strlen(dis);
for(i=0;i<x;i++)>
	{
		if((i+2)%2 ==0)
		{
			
			EvenArray[j]=Inputarray[i];
			j++;
		}
		else
		{
			OddArray[k]=Inputarray[i];
			k++;
		}
	}

Posted 23-Jun-16 1:25am

Member 11648410

Updated 23-Jun-16 16:48pm

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Comments

jeron1 23-Jun-16 10:13am

Have I completely missed something? You are doing nothing with the CString that supposedly contains the data to be processed, and CString has its own GetLength() method.

Member 11648410 23-Jun-16 22:49pm

strcpy(Inputarray,dis); forgot to add this ..Sorry

jeron1 24-Jun-16 10:31am

Can't you access elements of the CString the same way, with the [] operator? You could get rid of InputArray[], and strcpy(), the variable x, and alter the for loop to look like for(i = 0; i< dis.GetLength(); i++)

phil.o 24-Jun-16 0:23am

For oddity test, I suggest to use if ((i & 1) == 0) instead.

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OriginalGriff · Answer 1 · 2016-06-23T01:36:00

Well... that needs a little tweaking.
You aren't processing it correctly - your definition of "odd" and "even" excludes zero and unity.
Zero I can understand (it's neither odd nor even) but one is odd.
But to exclude them, it's simple: change the initial value of i:

C++

for(i=2;i<x;i++)>

Should do it.

(Do bear in mind that arrays in C / C++ / C# all start with element at index zero, not index 1: so in the string "12345" the character at index 2 is "3".
If your position values don't allow for that, you need to tweak your code slightly.

How to split a string into arrays

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How to split a string into arrays

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