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could not call a function that is defined in another

What I have tried:

var func1 = (function() {
function func2() {
console.log("wrkng");
};
})();
how can i call func2()???
func1.func2(); gives error saying func1 is undefined..
Posted
Updated 22-Aug-16 19:02pm

You Cannot! since it is a private function, use Module pattern[^] to expose it outside as
JavaScript
var func1 = (function () {
           func2 =  function() {
                console.log("wrkng");
           };
           return {func2:func2}

        })();


JavaScript
func1.func2()
 
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v2
AFAIK, you can't. The visibility scope of the inner function is limited to the function it is defined in.
 
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