Nested if else question

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sample output

enter type of the room: 1
enter the month: Dec
enter no of days: 3
enter type of the room: 2
enter the month: Jan
enter no of days: 4
enter type of the room: 0
total amount to be paid: .......

There are only 3 type of rooms. 1, 2 and 3. if user enters any other if should appear "Invalid room type". The question says can exit by entering 0 for the room type as shown in the sample output. but in my case it says invalid room type and after shows total amount. can you please help me.

What I have tried:

#include

Posted 15-Sep-16 2:50am

Member 12739755

Updated 15-Sep-16 3:03am

v2

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[no name] 15-Sep-16 8:55am

If you do not understand your homework assignment you should be asking your teacher.

Philippe Mori 15-Sep-16 9:07am

Where is your code. You won't learn anything if we do your whole homework!

Member 12739755 16-Sep-16 0:59am

I have uploaded my code

2 solutions

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This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

OriginalGriff · Answer 1 · 2016-09-15T03:03:00

C++

while(true)
   {
   // Get your value
   ...
   switch(enteredRoomType)
      {
      case 0:
         // All done - exit the app.
         exit(0);
      case 1:
      case 2:
      case 3:
         // All ok.
         break;
      default:
         cout << "Invalid room type";
         continue;
      }
   ...
   }

CPallini · Answer 2 · 2016-09-15T03:03:00

Solution 2

That shouldn't be nested if. That should be if chain (a sequence of if-else if statements) or, better a switch construct.

Posted 15-Sep-16 3:03am

CPallini

Nested if else question

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Solution 2

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Nested if else question

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