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sample output

enter type of the room: 1
enter the month: Dec
enter no of days: 3
enter type of the room: 2
enter the month: Jan
enter no of days: 4
enter type of the room: 0
total amount to be paid: .......

There are only 3 type of rooms. 1, 2 and 3. if user enters any other if should appear "Invalid room type". The question says can exit by entering 0 for the room type as shown in the sample output. but in my case it says invalid room type and after shows total amount. can you please help me.

What I have tried:

Updated 15-Sep-16 3:03am
[no name] 15-Sep-16 8:55am    
If you do not understand your homework assignment you should be asking your teacher.
Philippe Mori 15-Sep-16 9:07am    
Where is your code. You won't learn anything if we do your whole homework!
Member 12739755 16-Sep-16 0:59am    
I have uploaded my code

That shouldn't be nested if. That should be if chain (a sequence of if-else if statements) or, better a switch construct.
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   // Get your value
      case 0:
         // All done - exit the app.
      case 1:
      case 2:
      case 3:
         // All ok.
         cout << "Invalid room type";
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