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I am trying to insert data from a HTML form and PHP script to a MySQL Database.

I am able to connect to the MySQL server from the script but I cannot connect to the Database and table. So that I cannot insert data.

The error that triggers from the PHP script. The error is : Database is not selected !. But I have declared the name correctly.

Here I have uploaded the full solution .

Below I have added the HTML form and the PHP Script.

Could you please try to solve the issue if possible.

What I have tried:


    <title>Registration Form</title>
    <h2 align="center">Register a new customer</h2>
    <h3 align="center">Fill all fields</h3>
    <form action="insertdata.php" method="post">
        <table align="center">
                <td>First Name:</td>
                <td><input type="text" id="fname" name="fname" /></td>
                <td>Middle Name:</td>
                <td><input type="text" id="mname" name="mname" /></td>
                <td>Last Name:</td>
                <td><input type="text" id="lname" name="lname" /></td>
                <td>NIC / Driving License No:</td>
                <td><input type="text" id="NICNo" name="nicno" /></td>
                <td>Permanent Address Name:</td>
                <td><input type="text" id="paddress" name="paddress" /></td>
                <td>E-Mail Address:</td>
                <td><input type="text" id="email" name="email" /></td>
                <td><input type="text" id="telno" name="telno" /></td>
                <td>Mobile No:</td>
                <td><input type="text" id="mobileno" name="mobileno" /></td>
                <td>Date of Registration:</td>
                <td><input type="text" id="regdate" name="regdate" /></td>
            <td align="center"><input type="submit" />     <input type="reset" /></td>





$dbserver = 'localhost';
$username = 'root';
$password = '';

$dbname = 'car_rental';

$con = mysqli_connect($dbserver, $username, $password);

    echo "Not connected to server !";
    echo "Server connected !";

if(!mysqli_select_db($con, $dbname));
    echo "Database not selected !";

$fname = $_POST["fname"];
$mname = $_POST["mname"];
$lname = $_POST["lname"];
$nicno = $_POST["nicno"];
$paddress = $_POST["paddress"];
$email = $_POST["email"];
$telno = $_POST["telno"];
$mobileno = $_POST["mobileno"];
$regdate = $_POST["regdate"];

$sql = "INSERT INTO new_customers (FirstName, MiddleName, LastName, NICNo, PermanentAddress, EmailAddress, Telephone, Mobile, RegDate) VALUES ('$fname','$mname','$lname','$nicno','$paddress','$email','$telno','$mobileno','$regdate')";

if (!mysqli_query($con,$sql))
    echo "Data not inserted !";
    echo "Data inserted !";

header("refresh:300; url=form.php");


Updated 5-Nov-16 1:27am
Mohibur Rashid 5-Nov-16 5:46am
try calling the function mysqli_select_db
Chiranthaka Sampath 5-Nov-16 6:00am
Hi Rashid,

Thanks for the tip but I have already declared mysqli_select_db() function. Please refer the 'InsertData.php'
Peter Leow 5-Nov-16 7:39am
Have your verified that this 'car_rental' database does exist?
Mohibur Rashid 5-Nov-16 9:31am
instead of echo "database not selected !" call mysqli_error as CPallini suggested. Also, your message is not correct. But my guess will be same as Peter Leow, your database does not exists, or at least your database name spelling is wrong
Mohibur Rashid 9-Nov-16 0:40am
if it still does not work, just run this
mysqli_query($con, "USE $dbname"); and then use mysqli_error

same thing though.

also, let us know, how you have fixed them

1 solution

I would call mysqli_error($con)) in order to get additional info.

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