Vector string into int... But utilizing at.(I)?

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Hello,

I am somewhat familiar with converting using atoi in regards to a string to int:

C#

r.r= atoi(variable.c_str());

But how can I use this in conjuction with .at(i)?

If it matters, the string is a vector.

What I have tried:

C++

for (i = 1; i <= stringVariable.size; i++) {
		

MemberFunction(MemberFunction(atoi(stringVariable.at(i)), variable, variable);

}

Posted 6-Dec-16 16:59pm

Fence5

Updated 6-Dec-16 21:00pm

SoMad

v2

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Comments

Philippe Mori 7-Dec-16 10:32am

Write real code in your example.

2 solutions

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This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

User 59241 · Answer 1 · 2016-12-06T17:58:00

Solution 1

To utilise at(n) with atoi() use it thus:

C++

std::vector<std::string> v;

v.push_back("2222");

int i = atoi(v.at(0).c_str());

Posted 6-Dec-16 17:58pm

User 59241

Comments

KarstenK 7-Dec-16 3:13am

the solution is correct, but problematic in complex scenarios like some error handling.

CPallini · Answer 2 · 2016-12-06T21:00:00

Solution 2

There is a C++ way to do that, try:

C++

#include <iostream>
#include <sstream>
#include <vector>
using namespace std;

int main()
{
  vector < string > v{ "10", "20", "30" };

  for (const auto & x : v)
  {
    istringstream iss(x);
    int n;
    iss >> n;
    cout << n << endl;
  }
}

Posted 6-Dec-16 21:00pm

CPallini

v2

Comments

KarstenK 7-Dec-16 3:10am

Nice and funny ;-)

CPallini 7-Dec-16 3:16am

Thanks.

Vector string into int... But utilizing at.(I)?

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Vector string into int... But utilizing at.(I)?

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