What argument I have to pass to the function myfunk?

Question

3.00/5 (4 votes)

See more:

What function argument i have to pass to function Myfunk,c without changing the defition?

void MyFunc(int * & data) {data++;}
void main () {
 int a = 5;
 MyFunc(&a);
 cout << a;
}

What I have tried:

I have tried the address memory of the &a.

Posted 2-Feb-17 6:24am

Member 12975649

Updated 2-Feb-17 7:01am

Add a Solution

2 solutions

Add a Solution

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

CPallini · Answer 1 · 2017-02-02T06:52:00

Solution 1

It takes a reference to a pointer (to int).
Try, for instance:

C++

#include <iostream>
using namespace std;

void MyFunc(int * & data) {data++;}

int main ()
{

  int a [] = { 12, 15, 27, 42 };

  int * p = &a[2];

  cout << *p << endl;

  MyFunc( p );

  cout << *p << endl;
}

Posted 2-Feb-17 6:52am

CPallini

v2

Jochen Arndt · Answer 2 · 2017-02-02T07:01:00

You have to pass a reference to an int*:

C++

int someVal = 123;
int *pSomeVal = &someVal;
MyFunc(pSomeVal);

Because a reference must be an lvalue, you must create a variable rather than just passing the address of a variable which is not an lvalue.

Because your function is incrementing the pointer, using an array makes more sense (avoid out-of-bounds access):

C++

int someVals[] = { 1, 2, 3 };
int *pSomeVal = someVals;
MyFunc(pSomeVal);
cout << *pSomeVal;

What argument I have to pass to the function myfunk?

2 solutions

Solution 1

Solution 2

Add your solution here

Preview 0

What argument I have to pass to the function myfunk?

2 solutions

Solution 1

Solution 2

Add your solution here

Preview 0

Existing Members

...or Join us