How to POST value to PHP in the same page using jquery

Question

0.00/5 (No votes)

See more:

Hai,
I have one label and button. when i click button, i need display button value into label    
in same page without page reload in php

What I have tried:

$(function (){
$(".1234").click(function() {
$(".123").toggle();
var CID = $(this).val();

$.ajax({
type: "POST",
url: "php/test.php",
 
data:{C_ID:CID},
 success: function(data){
 alert(data);
});
});
});
 
in test.php;
$id = $_REQUEST["C_ID"];
 
but i can't get the button value

Posted 9-Feb-17 12:24pm

Nataraj Pandiyan

Updated 24-Nov-19 19:38pm

Add a Solution

2 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Peter Leow · Answer 1 · 2017-02-09T22:28:00

Why do you want to make a round trip to the server just to copy the button value to a label on the same page, can't you just do it with JavaScript or jQuery?
However,, if you insist:
This

success: function(data){
alert(data);

is missing a closing

I wonder why this

$(".123").toggle();

for?
You did not show your html code, make sure you button look similar to this:

<button class="1234" value="The button value that you want">click me</button>

In the test.php,

<?php
	if (isset($_REQUEST["C_ID"]))
   		echo $_REQUEST["C_ID"];
?>

Last but not least, you can achieve the same objective using just jQuery:

<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Untitled Document</title>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.1/jquery.min.js"></script>
<script>
$(document).ready(function(){
	
  $(".1234").click(function() {
	  
	  $('label').html($(this).val());

  })
	
})

</script>
</head>

<body>

<label></label>
<button class="1234" value="Hello, Button!">click me</button>

</body>
</html>

Member 14666978 · Answer 2 · 2019-11-24T19:38:00

$.ajax({
type: 'post',
dataType: 'json',
data: {id: testId},//Pass the id
});

`if(isset($_POST['id']) ){
$te = $_POST['id'];
echo $te;
}

else
{

echo $te;

}

How to POST value to PHP in the same page using jquery

2 solutions

Solution 1

Solution 2

Add your solution here

Preview 0