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I have written a very simple PHP program following this tutorial. I am using XAMPP Control Panel v3.2.2 and in it I am using Apache and MySQL. When I try to submit the for I am getting following error
Cannot POST /connect.php
When I open
through a browser, then it shows following error
Fatal error: Function name must be a string in ..\xampp\htdocs\test\connect.php on line 7

The error is isolated to POST only. Read till end

Here is the HTML.
<!DOCTYPE html>
    <title>test PHP</title>
        <form name="user reg" method="post" action="connect.php">
            <input type="text" name="firstName" value="">
            <input type="text" name="userName" value="">
            <input type="submit" name="submit" value="Submit">


$servername = "localhost";
$dbusername = "root";
$dbpassword = "";
$dbname = "testdb";

$firstName = $_POST('firstName');
$userName = $_POST('userName');

$conn = new mysqli($servername, $dbusername, $dbpassword, $dbname);

    die("Connection Failed: ".$conn->connect_error);
    echo "enter the first name";
    echo "enter the user name";

$sql = "INSERT INTO registeredusers (firstName, userName)
    VALUES('$firstName', '$userName')";

if($conn->query($sql) === TRUE){
    echo "data has been entered";
    echo "error". $sql."<br>".$conn->error;


What I have tried:

I have also looked into this it wasn't helpful. After opting suggested changes, as shown,
$firstName = $_POST['firstName'];
$userName = $_POST['userName'];

It gave following error.

Notice: Undefined index: firstName in C:\xampp\htdocs\test\connect.php on line 7
Notice: Undefined index: userName in C:\xampp\htdocs\test\connect.php on line 8
enter the first name

Following a similar post solution and editing php.ini. Here it states that editing php.ini file is not needed as XAMPP has all the required permissions needed on Windows.

After removing $_POST from
$firstName = $_POST['firstName'];
$userName = $_POST['userName'];

and setting the variables to some string, I can save data to MySQL

You can follow up here.
Updated 1-Jun-17 2:24am

1 solution

You are right for these corrections:
$firstName = $_POST['firstName'];
$userName = $_POST['userName'];

Next, look at the flow of your program, you have included 'connect.php' and its code will be executed every time the page is being loaded. What happened then? The two $_POST variables do not exist! That causes the error.
The solution is to use if condition to check for the existence of these two $_POST variables before proceeding with the rest of the PHP code, i.e.
if(isset($_POST['firstName'] && $_POST['userName']){
    $firstName = $_POST['firstName'];
    $userName = $_POST['userName'];
    // other code
theRealGreenz1 1-Jun-17 23:29pm
Thanks Peter Leow I will make these changes.

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