How to check if user's input is a string python3

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so, what if you are trying to check someone's input if the input is a string or not. BUT whenever you catch an exception in the statement the value of the variable gets deleted. and you can't print it anymore. how can you catch a exception and still print the VALUE of the input.
i hope you got what i said

Python

try:
    someValue =int(input('> '))
except ValueError:
    print(someValue)

[Edit]

The error is:

Python

NameError: name 'someValue' is not defined

What I have tried:

trying sys.stdin.read, sys.stdin.readline
and many other things

Posted 2-Aug-17 1:20am

Member 13341498

Updated 2-Aug-17 2:02am

Thomas Daniels

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Thomas Daniels · Accepted Answer · 2017-08-02T02:02:00

You can't use someValue in the except statement, because it would never be created if you enter the except block. someValue would contain the parsed integer, but if you can't do the parsing, the variable assignment will never happen. So "the variable gets deleted" is false, "the variable never gets created" would be a correct statement.

Try this instead:

Python

user_input = input('> ')
try:
    some_value = int(user_input)
except ValueError:
    print(user_input)

How to check if user's input is a string python3

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How to check if user's input is a string python3

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