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This is the view :

@foreach (var module in Model)
        if (module.Placeholder == "head")
            Html.RenderAction(module.Control, "ContentHtml", module.Content);


        <br />

And this is the controller :

public ActionResult Tabelar2(string content)

              var movies = db.ContentHtmls.Where(s => s.Content.Contains(content));

          return View(movies);

This works only when i set the content 'test1' in the url , example localhost:58881/Home/About/test1 , what I want is how to read the module.Content field into database in this row
Html.RenderAction(module.Control, "ContentHtml", module.Content);
, and then pass that value into the controller
public ActionResult Tabelar2(string content)
, so it can show only the News with that content. This line
Html.RenderAction(module.Control, "ContentHtml", module.Content);
goes to ContentHtml controller , to the certain Action based on module.Control , in this case Tabelar2 , and the route values should be the module.Content.

What I have tried:

I just explained the problem above
Updated 4-Sep-17 1:33am

1 solution

You need to encapsulate the POST BACK data in a FORM.

@using (Html.BeginForm()) {
        <!-- Fields to post back go here -->
        <input type="submit" value="Delete" /> |

More info here:
* FormExtensions.BeginForm Method (HtmlHelper) (System.Web.Mvc.Html)[^]
* ASP.NET MVC 4 Helpers, Forms and Validation | Microsoft Docs[^]
* mvc - How does @Html.BeginForm() works? - Stack Overflow[^]
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