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C program to print number of characters as per the count

Nuruddin Warsi asked:

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You are the encoded form of a data string as follows: consecutive
occurrences of a letter (up to 9) are represented by the letter
followed by the number of occurrences.

For example, the string

a9a3b2c4de

stands for the string

aaaaaaaaaaaabbccccdc

- that is, 12 consecutive occurrences of a, followed by 2 bs, and then
4 cs, followed by a d and finally c

Given an encoded form, you have to output the data string.

Its not entering the two if conditions


[edit]Tidy up, code block added, indentation sorted, spurious blank lines removed - OriginalGriff[/edit]

What I have tried:

#include<stdio.h>
int main()
    {
    int i,n,s;
    char a[100];
    scanf("%d",&s);
    for(i=0;i<s;i++)
        {
        scanf("%c",&a[i]);
        }
    for(i=0;i<s;i++)
        { 
        if((a[i]>='a' && a[i]<='z')&&(a[i+1]>='a'&& a[i+1]<='z'))
            {
            printf("%c",a[i]);
            }
        else if((a[i]>='a' && a[i]<='z') &&(a[i+1]>='2' && a[i+1]<='9'))
            {
            n=a[i+1];
            while(n>0)
                {
                printf("%c",a[i]);
                n=n-1;
                }
            }
        }
    if(a[s-1]>='a'&& a[s-1]<='z')
        {
        printf("%c",a[s-1]);
        }
    return 0;
    }
Tags: C

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