Deserialize json response string to class

Question

2.50/5 (2 votes)

See more:

I am getting JSON response string, which is:

[{"Id":1,"Name":"name1"},{"Id":2,"Name":"name2"},{"Id":3,"Name":"name3"}]

now if I try to deserialize this string into class object and also in XmlDocument, its not working. Instead I am getting null value in both Class object and XmlDocument object.

What I have tried:

I tried the following for deserializing into a class

using (HttpWebResponse resp = (HttpWebResponse)req.GetResponse())
{
  if (resp.StatusCode == HttpStatusCode.OK)
  {
    StreamReader rd = new StreamReader(resp.GetResponseStream());
    string str = rd.ReadToEnd(); //Here I can see the response JSON string
    Student std = JsonConvert.DeserializeObject<Student>(str);
  }
}

I tried the following for deserializing into XmlDocument

using (HttpWebResponse resp = (HttpWebResponse)req.GetResponse())
{
  if (resp.StatusCode == HttpStatusCode.OK)
  {
    StreamReader rd = new StreamReader(resp.GetResponseStream());
    string str = rd.ReadToEnd(); //Here I can see the response JSON string
    XmlDocument xDoc = new XmlDocument();
    xDoc = JsonConvert.DeserializeXmlNode(str);
  }
}

Posted 23-Oct-17 20:56pm

Kingshuk_SP

Updated 24-Oct-17 19:05pm

Add a Solution

3 solutions

Solution 1

Its a JSON array so parse it with Student Array

Student[] Students = JsonConvert.DeserializeObject<Student[]>(json);
            foreach (Student student in Students)
            {
                int id = student.Id;
                string name = student.Name;
                
            }

ensure the Student class looks like this

class Student
  {
      public int Id { get; set; }
      public string Name { get; set; }
  }

Posted 23-Oct-17 21:30pm

Karthik_Mahalingam

Updated 23-Oct-17 21:32pm

v3

Solution 3

To further expand on Karthik Bangalore's solution, you dont need to use an array when List<t> is available so here's what I would do:

C#

using Newtonsoft.Json;
using System.Collections.Generic;

namespace WorkingWithJson
{
    public class Person
    {
        public int Id { get; set; }
        public string Name { get; set; }
    }

    public class Working_with_json
    {
        public static void DeserializeJSON()
        {
            // our json string
            string json = @"[{""Id"":1,""Name"":""name1""},{""Id"":2,""Name"":""name2""},{""Id"":3,""Name"":""name3""}]";
            
            // deserializing to a list of type Person
            List<Person> people = JsonConvert.DeserializeObject<List<Person>>(json);

            // which can then be retrieved thus
            System.Console.WriteLine($"{people[0].Id} - {people[0].Name}");
        }
    }
}

Posted 27-Oct-17 3:22am

Member 13489209

Add a Solution

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Graeme_Grant · Accepted Answer · 2017-10-24T19:05:00

Solution 2

To expand on Karthik Bangalore solution, Working with JSON in C# & VB[^] is a CodeProject article written for Q&A questions like this one. It covers tools, including code generation, helper classes, and full working samples that you can download and run.

Posted 24-Oct-17 19:05pm

Graeme_Grant

Comments

Kingshuk_SP 25-Oct-17 2:42am

Nice article Graeme :) Thanks and Cheers :)

Graeme_Grant 25-Oct-17 3:08am

You are welcome. Too much to post here... Glad that it helped.

Deserialize json response string to class

3 solutions

Solution 1

Solution 2

Solution 3

Add your solution here

Preview 0

Deserialize json response string to class

3 solutions

Solution 1

Solution 2

Solution 3

Add your solution here

Preview 0

Existing Members

...or Join us