Please explain me the output.i think the output should be 8 but it is 10.why its giving 10 as output?

Add a couple of cout lines to the code and then run the code under the debugger, after putting a breakpoint on the first line under int main(). Step through the code line-by-line in the debugger, examining the contents of the variables before and after each line of code is executed and it should become obvious what's going on.

<pre>int main()
{
    int a[] = { 5, 7, 9, 11, 14 };

    int *p = a + 2;

    cout << *p << endl;

    cout << ++*p++ << endl;

    cout << *p << endl;
}

The debugger is a tool to debug YOU and your understanding of the code, not the code itself. You have to learn to use this tool or you're just going to be guessing at what you're code is really doing.

How a compiler and CPU interpret and execute the code can be vastly different from how you interpret and execute the code in your head.

Putting all else aside, which is not easy

int *p=a+2; // Increments two sizeof(int) - that is, two elements NOT two bytes

So, since a is the address of a[0] then a+2 is the address of a[2]
That means it's pointing to 9.
If you increment 9 it give you 10.

Make sense, now? Good. Now go study point arithmetic and usage in C/C++. It's incredibly useful, powerful, and without mastering it you're wasting your time.

Do not combine things in same line if you don't understand what you combine.
Change your code to:

#include <iostream>
using namespace std;

int main() {
  int a[] = { 5,7,9,11,14};
  cout<<"A:" << *a << endl;
  int *p= a+2; // this is pointer arithmetic 
  cout<<"B:" << *p << endl;
  // the result comes from
  cout<<"C:" << ++(*p) << endl;
  cout<<++*p++;
}