Regarding this SQL query, how can I output list of 28/30/31 days according to user's choice of certain month and year

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The problem is I am stuck at how to output 28/30/31 days according to user's choice of certain month and year, here is my code:

What I have tried:

declare @FromDate as datetime;
declare @ToDate as datetime;
declare @OperID as varchar(20) = 'OP1';
declare @Year as int = 2018
declare @Month as int = 1

set @FromDate = convert(date,convert(varchar,@Year) + '-' + convert(varchar,@Month) + '-01')
set @ToDate = dateadd(d,-1,DATEADD(m, 1, @FromDate))

select Branch_no, operid, clock_date, [I], [O]
from
( select Branch_no, operid, 
    convert(date, clock_date) as clock_date, 
    convert(time, clock_date) as clock_time, 
    clock_type, Workstation_no
  from ROSTER_TIMECLOCK
  where Clock_date >=CONVERT(DATETIME, @FromDate, 102)
    and Clock_date <=CONVERT(DATETIME, @ToDate, 102)
    and OperID=@OperID
) as TheClock
PIVOT
( min(clock_time)
  FOR clock_type in ([I],[O])
) as ThePivot

Posted 28-Jan-18 14:32pm

Member 11850495

Updated 10-Feb-18 16:23pm

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Comments

RedDk 29-Jan-18 13:56pm

Qu'est-ce que c'est "ROSTER_TIMECLOCK"?

Member 11850495 29-Jan-18 17:22pm

ROSTER_TIMECLOCK is the table that I do the query.

Richard Deeming 30-Jan-18 12:36pm

@FromDate and @ToDate are already datetime values, so there's no need to CONVERT them.

Other than that, I can't see anywhere in your code that would generate a fixed number of days. You're selecting all of the records which fall within the month, so what's the problem?

Herman<T>.Instance 1-Feb-18 8:07am

--> WHERE MONTH(Clock_Date) = @Month AND YEAR(Clock_Date) = @Year AND OperID=@OperID

Then you select all month data for a given year, so 28/29/30 or 31 days is no issue!

Member 11850495 1-Feb-18 19:27pm

Thank you sir

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Member 13672047 · Answer 1 · 2018-02-10T16:23:00

Solution 1

declare @Year as int = 2018
declare @Month as int = 1
select day(dateadd(dd,-1,dateadd(mm,1,datefromparts(@Year,@Month,1))))

Posted 10-Feb-18 16:23pm

Member 13672047

Comments

Richard Deeming 13-Feb-18 12:28pm

DateFromParts[^] was added in SQL Server 2012. At the same time, they added EOMonth[^] to get the last day of the month, which would simplify your code slightly. :)

SELECT Day(EOMonth(DateFromParts(@Year, @Month, 1)))