Get all the employees latest document date in SQL server

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Get all the employees latest Document date in sql server

No	Employee	DocumentDateNew
1	Employee1	3/22/2018
2	Employee1	5/22/2018
3	Employee1	10/23/2017
4	Employee2	3/21/2018
5	Employee2	6/22/2018
6	Employee2	10/23/2017
7	Employee2	10/12/2017
8	Employee3	3/22/2018
9	Employee3	11/10/2017

i need result like

NO	Employee	DocumentDateNew
1	Employee1	3/22/2018
4	Employee2	3/21/2018
8	Employee3	3/22/2018

What I have tried:

Get the record all the employee based on latest documents date

Posted 22-Mar-18 18:39pm

DhananjayanP

Updated 23-Mar-18 7:26am

v3

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3 solutions

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itsmypassion · Answer 1 · 2018-03-22T18:56:00

Solution 1

SQL

SELECT EMPLOYEE,MAX(DOCUMENTDATE) FROM EMPLOYEETABLE GROUP BY EMPLOYEE

Posted 22-Mar-18 18:56pm

itsmypassion

Comments

DhananjayanP 23-Mar-18 1:33am

thank you for your answer, but I am getting EMPLOYEE name as Duplicate

dkamble 10358990 · Answer 2 · 2018-03-22T18:59:00

Solution 2

select Employee, max(DocumentDateNew) as DocumentDateNew from emptable group by Employee

Posted 22-Mar-18 18:59pm

dkamble 10358990

Comments

DhananjayanP 23-Mar-18 2:01am

thank you for your answer, but I am getting EMPLOYEE name as Duplicate

itsmypassion 23-Mar-18 2:28am

Do not include Column "No" in Group by List.

Richard Deeming · Answer 3 · 2018-03-23T07:27:00

If you need to include the "No" column:

SQL

WITH cte As
(
    SELECT
        No,
        Employee,
        DocumentDateNew,
        ROW_NUMBER() OVER (PARTITION BY Employee ORDER BY DocumentDateNew DESC) As RN
    FROM
        YourTable
)
SELECT
    No,
    Employee,
    DocumentDateNew
FROM
    cte
WHERE
    RN = 1
;

Demo[^]
ROW_NUMBER (Transact-SQL) | Microsoft Docs[^]

NB: Your expected output is wrong. Taking Employee1 as an example, 22nd May 2018 is later than 22nd March 2018, so the output should return row 2, not row 1.

Get all the employees latest document date in SQL server

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Get all the employees latest document date in SQL server

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