Calling function in nested IF in Python

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I have to take the user inputs of bird names and check in the list of bird_names.

I have tried the following code:
first input: butterfly
output:

2nd try fail, please do 3rd try

On 2nd try
input: parrot
output: <

1st try fail, do 2nd try

'

The code in italics is not working.

Kindly tell me where I am wrong in my logic.

Thanks in advance!

What I have tried:

bird_names=('crow', 'parrot', 'eagle')
def bird_guess():
    bird_guess1=input('Enter the bird guess :')
    return bird_guess1

bird_guess()

if(bird_guess not in bird_names):
        print('1st try fail, do 2nd try')
         bird_guess()
        if(bird_guess not in bird_names):
            print('2nd try fail, please do 3rd try')
            bird_guess()
            if(bird_guess not in bird_names):
                print('Sorry, exhausted tries')
            else:
                print('corect on 3rd try')
        elif(bird_guess  in bird_names):
                    print('good work! correct on 2nd try')
elif(bird_guess  in bird_names): 
                        print('great work!, correct on 1st try itself')
    
else:
    print('Not Valid')

Posted 6-Jun-18 23:57pm

Member 13842073

Updated 12-Feb-20 4:46am

v2

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Comments

Richard MacCutchan 7-Jun-18 5:22am

Why not just use a simple loop that counts the number of tries, and exit the loop when maximum try count is reached?

Also, you are not capturing the value returned by your function.

Member 13842073 7-Jun-18 5:37am

Hi Richard,
Thanks for the reply.

I have tried capturing the value and still getting the same result.

I am new to programming, and lagging in certain concepts.

Could you please further explain on this?
Thanks again

Member 13842073 7-Jun-18 6:24am

Why is it mandated to capture the return value of a function?

Richard MacCutchan 7-Jun-18 6:31am

Because you need to capture the return value in a variable. If you do not do that then the value is thrown away. Think of it as asking someone to write something on a piece of paper for you. When they have finished, you need to take the paper in order to see what they have written.

Member 13842073 7-Jun-18 6:46am

Cool! Thank you so much for explaining

3 solutions

Solution 2

Try this:

Python

bird_names=('crow', 'parrot', 'eagle')
def bird_guess():
    bird_guess1=input('Enter the bird guess :')
    return bird_guess1

def birdtest():

    for count in range(1,4):
        bird = bird_guess()
        if(bird not in bird_names):
            print('try', count, 'failed, ', end='')
            if count < 3:
                print('try again')
            else:
                print('no more guesses allowed.')
                break
        else:
            print("correct, it is in the list")
            break

But, as a new programmer your time would be better spent following The Python Tutorial[^]

Posted 7-Jun-18 1:09am

Richard MacCutchan

Comments

Member 13842073 7-Jun-18 6:17am

Thanks, Richard.
Once I am through the basics, I will try your solution as well.
Thanks again.

Solution 3

# [ ] Solution

# [ ] Create the "Guess the bird" program

bird_guess = input()
bird_name = "eagle, falcon, crow, dove, pigeon,"

bird_guess in bird_name

if bird_guess == "eagle":
print("1st Try!: ", bird_guess in bird_name)
bird_guess = input()

if bird_guess =="crow":
print("2nd Try!: ", bird_guess in bird_name)
bird_guess = input()

if bird_guess =="falcon":
print("3rd Try!: ", bird_guess in bird_name)
bird_guess = input()

if bird_guess =="dove":
print("4th Try!: ", bird_guess in bird_name)
bird_guess = input()

if bird_guess =="pigeon":
print("5th Try!: ", bird_guess in bird_name)
bird_guess = input()

else:
print("Try Again!: ")
bird_guess = input()
if bird_guess =="crow":
print("2nd Try!: ", bird_guess in bird_name)
bird_guess = input()

else:
print("2 Try Again!: ")
bird_guess = input()
if bird_guess =="falcon":
print("3nd Try!: ", bird_guess in bird_name)
print("Sorry Out turn: ")

Posted 12-Feb-20 4:46am

Member 14742689

Updated 12-Feb-20 4:48am

v2

Comments

CHill60 12-Feb-20 9:53am

Don't do it this way. Really, don't do it this way.

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This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

CPallini · Accepted Answer · 2018-06-07T00:49:00

You are using bird_guess function, instead of its return value in your tests. Try

Python

bird_names=('crow', 'parrot', 'eagle')
def bird_guess():
    bird_guess1=input('Enter the bird guess :')
    return bird_guess1

guess = bird_guess()

if(guess not in bird_names):
    print('1st try fail, do 2nd try')
    guess = bird_guess()
    if(guess not in bird_names):
        print('2nd try fail, please do 3rd try')
        guess = bird_guess()
        if(guess not in bird_names):
            print('Sorry, exhausted tries')
        else:
           print('corect on 3rd try')
    else:
       print('good work! correct on 2nd try')
else:
    print('great work!, correct on 1st try itself')

Calling function in nested IF in Python

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Calling function in nested IF in Python

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