How do I decode cdata section of different XML files having different datawidth

Question

0.00/5 (No votes)

See more:

Copy Code

<?xml version="1.0" encoding="UTF-8"?>
<TesterLog Version="1">
  <TestProperties>
    <Item name="IUT Name" value="Reference"/>
  </TestProperties>
  <SignalData SamplingPeriod="1000.000 ns" DataWidth="16 bit">
    <Signal>
      <Id>IUT_RX</Id>
      <InitState>1</InitState>
      <![CDATA[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]]>
    </Signal>
    <Signal>
      <Id>CCT_TX</Id>
      <InitState>1</InitState>
      <![CDATA[HQFPAVkBiwGVAZ8BqQHHAdEBAwINAjUCPwJxAnsCrQK3AsEC1QLzAv0CEQMbAzkDTQNrA3UDfwOJA7sDxQPtA/cDKQQzBEcEUQSDBI0EtQTJBN0E5wTxBAUFDwUZBS0FNwVBBUkXUxfbGeUZ1ijgKMc20Ta4N0==]]>
    </Signal>
//////////////////////////////////////////////////////////////////////////////////////////////////////
  </SignalData>
</TesterLog>

this is my xml file. i am able to read the the information. but my code is very static. it decodes only those xml files in which DataWidth are 16 bits. DataWidth is the attribute of Element SignalData. I want my code to be in such a way that it should work for every type of DataWidth. e.g 8,16,24,32,40,48....64 etc.

What I have tried:

Copy Code

byte[] data = Convert.FromBase64String(cData);

Copy Code

int oldResult = 1;

Copy Code

ushort[] arr16 = new ushort[data.Length];

Copy Code

for (int i = 0; i < arr16.Length; i++)
            {
                arr16[i] = data[i];
            }

Copy Code

for (int i = 0; i < arr16.Length; i += 2)
                {
                var resultant = (arr16[i]) | (arr16[i + 1] << 8); //285 is the transition state.. As in xml file the initial state is 1 give. so signal will remain 1 till 284. on 285 signal becomes 0 and it will remain 0 before we reach another transition state... this will keep on doing like that.

Copy Code

 for (int j = oldResult; j < resultant; j++)
                   {
                       Console.Write(initialState); // printing signal value. it can be either 1 or 0
 
                        
                    }
               
                   if (initialState == 1)
                        initialState = 0;
                    else
                       initialState = 1;

                    oldResult = resultant;

               
                }
Console.WriteLine();

Posted 11-Jun-18 0:09am

hamid18

Updated 11-Jun-18 9:34am

v2

Add a Solution

2 solutions

Add a Solution

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Jochen Arndt · Accepted Answer · 2018-06-11T00:52:00

So you have samples with different number of bits per sample. To avoid using different types of output arrays, you can store the result in the largest supported width (here 64).

Untested example:

C#

Copy Code

// byte[] data is the input
// dataWidth is bits per sample (must be multiple of 8 and not larger than 64)

// bytes per sample
int bytes_per_sample = dataWidth / 8;
// Optional supporting dataWidth not being a multiple of 8
//if (dataWidth % 8)
//    bytes_per_sample++;

// total number of samples
int num_samples = data.Length / bytes_per_sample;
UInt64[] samples = new UInt64[num_samples];
for (int i = 0; i < num_samples; i++)
{
    // Assign the lowest byte (the only with 8 bit samples)
    samples[i] = data[i * bytes_per_sample];
    // Add the remaining bytes each shifted left by multiples of 8
    for (int j = 1, uint shift = 8; j < bytes_per_sample; j++, shift += 8)
    {
        samples[i] |= data[i * bytes_per_sample + j] << shift;
    }
}

Note that the above assumes the first bytes in the input stream are the lower bytes. If that does not apply, the above code has to be modified accordingly.

Patrice T · Accepted Answer · 2018-06-11T09:36:00

Quote:
How do I decode cdata section of different XML files having different datawidth

No matter what is your data, base 64 encoding is done on an array of bytes, so base64 decoding can only give you an array of bytes, no matter its meaning.
So, once you have bytes, you have read them by groups depending on DataWidth.

How do I decode cdata section of different XML files having different datawidth

2 solutions

Solution 1

Solution 2

Add your solution here

Preview 0

How do I decode cdata section of different XML files having different datawidth

2 solutions

Solution 1

Solution 2

Add your solution here

Preview 0

Existing Members

...or Join us