Why does the 'output' variable in this code get reset every iteration?

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Hi guys, I'm reading a JS book at the moment and one of the challenges had us loop over all integers between 1 - 100 and write "Fizz" if it's divisible by 3, "Buzz" if it's divisible by 5 and "FizzBuzz" if it's divisible by both, otherwise just log the number. I managed to work out the code for the problem but I'm unsure as to why the 'output' declaration gets reset every iteration rather than storing a long line of Fizzes and Buzzes. Here's the code:

for (let num = 1; num <= 100; num++){
	let output = "";
	if(num % 3 == 0) output += "Fizz";
	if(num % 5 == 0) output += "Buzz";
	console.log(output || num);
    }

What I have tried:

I've tried googling the question but I can't find anything specific as to why a variable sometimes resets each iteration, whereas sometimes it gets stored over and over to concatenate everything.

Posted 5-Jul-18 2:24am

Member 13899723

Updated 5-Jul-18 2:34am

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User 7429338 · Accepted Answer · 2018-07-05T02:34:00

Solution 1

It's because you declare it inside the loop. Declare it outside the loop to concatenate each iteration:

let output = "";
for (let num = 1; num <= 100; num++){
	if(num % 3 == 0) output += "Fizz";
	if(num % 5 == 0) output += "Buzz";
	console.log(output || num);
}

Posted 5-Jul-18 2:34am

User 7429338

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Member 13899723 5-Jul-18 8:45am

@Thaddeus Jones Ahhh that makes sense, every time it loops it sets the value to "" again, whereas if it were outside the loop it wouldn't get reset as it's not beeing reevaluated... Thanks for the clarity :)

CPallini 5-Jul-18 9:00am

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Why does the 'output' variable in this code get reset every iteration?

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Why does the 'output' variable in this code get reset every iteration?

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