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You are given a string S of lowercase English letters with length N. You are allowed to (but don't have to) choose one index in this string and change the letter at this index to any other lowercase English letter. The cost of this operation is the absolute value of the difference of ASCII values of the new letter and the original letter; let's denote it by X

Next, consider the number of pairs of indices (i,j)
in the resulting string (the string after changing one letter, or the original string if no letter was changed) such that 1≤i<j≤N and Si<Sj. Let's denote it by Y

Find the minimum possible value of X+Y?

For example

as in dcba there is no pair (i,j) Si<Sj so answer is 0.

What I have tried:

i tried to change the minimum element to maximum and counted the number of pairs and also tried to changed maximum to minimum and counted pairs and printed min of all three.
Posted
Updated 8-Jul-18 11:10am

## Solution 1

So, you show no attempt to solve the problem yourself, you have no question, you just want us to do your HomeWork.
HomeWork problems are simplified versions of the kind of problems you will have to solve in real life, their purpose is learning and practicing.

We do not do your HomeWork.
HomeWork is not set to test your skills at begging other people to do your work, it is set to make you think and to help your teacher to check your understanding of the courses you have taken and also the problems you have at applying them.
Any failure of you will help you to learn what works and what don't, it is called 'trial and error' learning.
So, give it a try, reread your lessons and start working. If you are stuck on a specific problem, show your code and explain this exact problem, we might help.

As programmer, your job is to create algorithms that solve specific problems and you can't rely on someone else to eternally do it for you, so there is a time where you will have to learn how to. And the sooner, the better.
When you just ask for the solution, it is like trying to learn to drive a car by having someone else training.
Creating an algorithm is basically finding the maths and make necessary adaptation to fit your actual problem.
Member 13903102 8-Jul-18 22:24pm

i am just stuck with character changing part rest i can calculate but how to decide which character should i change to minimise? i just need a little hint in that direction and i will hopefully solve it...
Patrice T 8-Jul-18 23:04pm

That is the subject of the challenge.
Finding an efficient way to get the answer.
Member 13903102 8-Jul-18 23:08pm

ok i will try my best and sorry i am just really new to codeproject so i asked a really bad question, will keep in mind and thanks for your help i feel motivated!
Patrice T 8-Jul-18 23:12pm

First find a way to find the answer.
Member 13903102 8-Jul-18 23:31pm

i can try my best!

## Solution 2

We do not do your homework: it is set for a reason. It is there so that you think about what you have been told, and try to understand it. It is also there so that your tutor can identify areas where you are weak, and focus more attention on remedial action.

Try it yourself, you may find it is not as difficult as you think!

If you meet a specific problem, then please ask about that and we will do our best to help. But we aren't going to do it all for you!
Member 13903102 8-Jul-18 22:27pm

just wanted a little hint for the character changing part and i am really new here didn't know much about how to ask a proper question sorry for that..
OriginalGriff 9-Jul-18 1:29am

That's ok - but when you post up homework and show no attempt to do it yourself, you aren't going to get help anywhere! :laugh:
Member 13903102 9-Jul-18 2:03am

i tried it with more strategy and what i found out is that i have to continue if the elements are in decreasing order or constant but this strategy also failing as is S=cdce and i change 2nd c it won't be optimal as changing 1st c to e gives the optimal answer ... i am still trying but can you tell me am i going in the right direction?? and also is merge sort is of any help here/?? and sorry for posting the complete question

## Solution 3

This is a question from on-going challenge, I don't think it is appropriate to ask it while the challenge is going on.

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