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I've defined one function which verifies that function argument is (list, tuple, dictionary and string) type of datatype using if-else statement and type function of python, but the problem is when i'm giving argument as list and set it matched perfectly but when i give tuple or string or dictionary it give error i'm not getting it beacause i'm a beginner so help needed

What I have tried:

def anything(arg):
        if type(arg) == list:
            print 'yes it\'s a list element : {}'.format(arg)
        elif type(arg) == set:
            print 'this is a set: {}'.format(arg)
        # elif type(arg) == dict(arg):
        #     print 'this is a dictionary element {}: {}'.format()
        elif type(arg) == tuple:
            print 'this is a tuple: {}'.format(arg)
        elif type(arg) == str:
            print 'this is a string: {}'.format(arg)
        else:
            print ('Invalid format')

# anything(arg = {'arg' : 'ashish'}) #NOT WORKING
anything(arg = ['ashish'])
anything(arg = {'set'})
anything(arg = ('tuple')) #HERE TUPLE ALSO PROVIDE TYPE STRING HOW??
anything(arg = 'string') 
Python

Posted
Updated 17-Sep-18 4:20am

1 solution

This appears to work under Python 3, I suggest you upgrade. Also see 3. Data model — Python 3.4.9 documentation[^].
 
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