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hi
have been doing this assignment and the deadline is due. it is a website where it have to run on the server

I have tried running it but keep breaking down, no output, am not even getting a php error, nothing I think it is something within the code what is causing it but cant say for sure

I need a third or maybe a fourth eye.

What I have tried:

this is what i have tried so far

<pre><?php

		error_reporting(E_ERROR | E_WARNING | E_PARSE | E_NOTICE);
		
		
		if(isset($_POST['register_user']))
		{
			//capture the variable from the form and store in php variables
			
			
			$title=$_POST['title'];
			$fullname=$_POST['fullname'];
			$lastname=$_POST['lastname'];
			$screenname=$_POST['screenname'];
			$email=$_POST['email'];
			$gender=$_POST['gender'];
			$address=$_POST['address'];
			$mypwd=$_POST['mypwd'];
			
			//connecting to the server
			
			include'db_server.php';
			
			$conn = mysqli_connect($db_host,$db_username,$db_password) or die (mysqli_connect_error());
			
			//select the database you want to query
			
			mysqli_select_db($conn, 'national_wonders') or die (mysqli_error($conn));
			$sql = "SELECT * FROM members WHERE screenname='$screenname'";
			$result = mysqli_query($conn, $sql) or die ("ERROR:" .mysqli_error());
			$rowcount = mysqli_num_rows($result);
			
			if($rowcount >= 1)
			{
				echo"<script type=\"text/javascript\">
					alert('Username already exits!!');
					window.location=\"../php/popup.php\";
					</script>";
			}
			else
			{
				//insert data into table
				
				$sql = "INSERT INTO members
				VALUES('$title', '$fullname', '$lastname', '$screenname', '$address', '$email', '$gender',  'md5('$mypwd))";
			
				if(mysqli_query($conn,$sql))
				{
					echo"<script type=\"text/javascript\">
					alert(Welcome);
					window.location=\"login.php\";
					</script>";
				}
				else
				{
					echo "Error inserting values into database";
				}
				
			
			}
			
		}	
			
?>	
Posted
Updated 22-Mar-19 0:30am
Comments
Richard Deeming 22-Mar-19 12:49pm    
MD5 is no longer considered secure enough for password storage. You should be using PHP's built-in password hashing methods:
PHP: password_hash[^]
PHP: password_verify[^]

PHP
$sql = "INSERT INTO members VALUES('$title', '$fullname', '$lastname', '$screenname', '$address', '$email', '$gender',  'md5('$mypwd))";

Not necessary a solution to your question, but another problem you have.
Never build an SQL query by concatenating strings. Sooner or later, you will do it with user inputs, and this opens door to a vulnerability named "SQL injection", it is dangerous for your database and error prone.
A single quote in a name and your program crash. If a user input a name like "Brian O'Conner" can crash your app, it is an SQL injection vulnerability, and the crash is the least of the problems, a malicious user input and it is promoted to SQL commands with all credentials.
SQL injection - Wikipedia[^]
SQL Injection[^]
SQL Injection Attacks by Example[^]
PHP: SQL Injection - Manual[^]
SQL Injection Prevention Cheat Sheet - OWASP[^]
How can I explain SQL injection without technical jargon? - Information Security Stack Exchange[^]
Quote:
I have tried running it but keep breaking down, no output, am not even getting a php error, nothing I think it is something within the code what is causing it but cant say for sure

Your code do not behave the way you expect, or you don't understand why !

There is an almost universal solution: Run your code on debugger step by step, inspect variables.
The debugger is here to show you what your code is doing and your task is to compare with what it should do.
There is no magic in the debugger, it don't know what your code is supposed to do, it don't find bugs, it just help you to by showing you what is going on. When the code don't do what is expected, you are close to a bug.
To see what your code is doing: Just set a breakpoint and see your code performing, the debugger allow you to execute lines 1 by 1 and to inspect variables as it execute.

Debugger - Wikipedia, the free encyclopedia[^]

Mastering Debugging in Visual Studio 2010 - A Beginner's Guide[^]
Basic Debugging with Visual Studio 2010 - YouTube[^]

phpdbg | php debugger[^]
Debugging techniques for PHP programmers[^]

The debugger is here to only show you what your code is doing and your task is to compare with what it should do.
 
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Comments
Maciej Los 22-Mar-19 3:04am    
5ed!
Patrice T 22-Mar-19 3:17am    
Thank you
How about making sure that the following condition is actually met?
if(isset($_POST['register_user']))
		{
    ...
}
If not, the whole body between the brackets will never be executed.
 
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