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I am having .net application and I have an xml document.I want to get the values of childnodes and put it into notepad.After I run the program the error is occurs.
"Data at the root level is invalid. Line 1, position 1.".Plz help me.Below is the code

XmlDocument xml = new XmlDocument();
       xml.LoadXml("C:/Documents and Settings/sridharan/Desktop/RTSLINK FOR TALLY/XMLFile3.xml");
       XmlNodeList xnlist = xml.SelectNodes("/Names/Name");
       foreach (XmlNode xn in xnlist)
           string firstname = xn["firstname"].InnerText;
           string lastname = xn["secondname"].InnerText;
           Console.WriteLine("Name:{0} {1}", firstname, lastname);

Everything is hard-coded. Very bad code.
sridharan28 18-May-11 1:27am
thanks for ur reply
sridharan28 18-May-11 1:25am
Thanks alot for your reply.Please give me suitable answer
I commented to the answer by S Mewara. I don't see the problem you report from your code. Are you sure this is the same code as the one which cause the problem? Perhaps you did not properly reported a problem. Check it up. Catch all exceptions around the code which throws it and dump exception stack, don't forget all inner exceptions (recursively); show the code lines in code file.
OK, you got a real answer. I suggest you do it right. It's easy, too. Please see my solution.

Similar issue discussed[^] here at length.

Few possible reasons are:
1. Not a well formed XML
2. Having a white space just before the root element
3. Wrong reference of the file
4. Encoding specified in XML document

Have a look at this discussion[^] too.

Apart from above answer, try two things:
1. Use xml.Load instead of xml.LoadXml method.
2. If 1 does not do, put this as the first line (make sure no space before the first character)
<?xml version="1.0" encoding="utf-8"?>
I'm not sure. First, items 1, 2 and 4 is the same as 1. Secondly, you see the XML code, it looks like well-formed. Item 3 is not applicable (see the error message).
Most probably, OP did not report the problem correctly...
Sandeep Mewara 18-May-11 1:46am
In a sense, agree 1,2 & 4 sounds same. But 1 is just for opening/closing tags. :)

Based on the thread references, I see that 3 can be the reason... though I totally agree again. To me, point 2 or 4 has highest chance.

Meanwhile, since you posted these comments, let me read more on what and why of this error - if I get anything else, I will share with you.
No! 1 is not just about tags. There is a whole lot of well-formed rules. See my comment below. Why doing all that?
sridharan28 18-May-11 1:26am
Exactly i am getting the error "Data at the root level is invalid. Line 1, position 1."
Sandeep Mewara 18-May-11 1:51am
Can you try putting this as the first line:
<?xml version="1.0" encoding="utf-8" ?>
Parser can work without it if I'm not much mistaken... good to check up... even if so, it wouldn't hurt, of course.
Sandeep, you know what? I see no point for OP to ram this problem.
Instead of using this naive home-baked approach to serialization, why not using ready-to-use technology which will serialize and deserialize everything automatically?

Please see my answer.
Here is the alternative. I would totally avoid this approach. I don't see why you need to deal with XML manually. Use Data Contract. It will robustly save your data model to XML and restore it back; the schema will be created on the fly. This is the most non-intrusive method as well: you only add attributes [DataContract] and [DataMembers].


Here's what your problem is:

XmlDocument has 2 load methods for loading XML

XmlDocument xml = new XmlDocument();

the passed paramater here should be a valid xml string.

the method you want is

XmlDocument xml = new XmlDocument();

Also, the XPath is case sensitive (Names is different than name)

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