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sir i created the pointer array:

char *p[10];

i want to covert to the char*;

i use typecasting

char *a = (char*)p;

Is it correct..

how can i decast that . and how to get the data back..

1 solution

char *p[10];
char *a = (char*)p;
Is not right (that's why you needed to add the cast)

char* p[10] creates an array of ten character pointers, char *a creates a character pointer.
In order to load the value of p into a, it needs to be a char**:
char *p[10];
char **a = p;
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PrafullaVedante 30-Jul-11 5:32am    
Perfect. My 5 :)

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