remove a simple error or warning in this program please

Question

1.50/5 (2 votes)

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C++

#include<stdio.h>               
  int main()
  {
  int l;
 l=(int *)malloc(1000);
  int a[l][l],c,d,n,i,j,q1=0,q2=0,q3=0,q4=0,will=1,b[20][20],k=0;
  char p;
  //printf("enter the number of co ordinate");
  scanf("%d",&n);
  for(i=0;i<n;i++)>
  for(j=0;j<2;j++)
  scanf("%d",&a[i][j]);
  void quadrant(int temp1,int temp2)
  {
                   
         if(temp1>=0&&temp2>=0)
        q1++;
      else if(temp1>=0&&temp2<=0)
        q2++;
      else if(temp1<0&&temp2<0)
        q3++;
      else if(temp1<=0&&temp2>=0)
         q4++;
 
   }
//printf("enter no of operations");
scanf("%d",&will);
                
while(will>0)
{

p=getchar();
scanf("%c",&p);
switch(p)
{
case 'x': 
                scanf("%d %d",&c,&d);
                  for(i=c-1;i<d;i++)>
                  a[i][1]=-(a[i][1]);break;
case 'y': 
                scanf("%d %d",&c,&d);
                for(i=c-1;i<d;i++)>
                a[i][0]=-(a[i][0]);break;
case 'c':       scanf("%d %d",&c,&d);
                for(i=0;i<=n-1;i++)
                {
                 int temp1,temp2;
                 temp1=a[i][0];
                 temp2=a[i][1];
              
                 quadrant(temp1,temp2);
                } 
               b[k][0]=q1;
               b[k][1]=q2 ;
               b[k][2]=q3;
               b[k][3]=q4; 
             
                  k=k+1; 
    q1=0;
    q2=0;
    q3=0;
    q4=0; 

                 
                  break;
case 'p':   printf(" the co-ordinates are:\n");
               for(i=0;i<n;i++)>
               {
                 for(j=0;j<2;j++)
                {
              printf("%d   ",a[i][j]);
                 }
                printf("\n");
                 } 
                 break;                               
     
default: printf("enter the correct choice\n");break;
}
if(will==1)
for(i=0;i<k;i++)>
{
printf("%d %d %d %d\n",b[i][0],b[i][1],b[i][2],b[i][3]);

}
will--;
}
}</stdio.h>

Posted 5-Sep-11 2:41am

kesavahariprasad

Updated 5-Sep-11 2:56am

JF2015

v4

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Comments

Wendelius 5-Sep-11 8:44am

And the error would be...

CPallini 5-Sep-11 8:59am

What is the 'simple error'?

kesavahariprasad 5-Sep-11 9:07am

i have to allocate memory for array in my program using malloc function

[no name] 5-Sep-11 9:02am

What it dose ""? look at the bottom of your code snippets.

kesavahariprasad 5-Sep-11 9:09am

my problem is i have toallocte memory for my array using malloc

Sergey Alexandrovich Kryukov 5-Sep-11 11:32am

Still no explanation. What's the problem? Purpose of this code?
--SA

Chuck O'Toole 6-Sep-11 2:20am

This is the 3rd time I've seen this identical program, even formatted the same. Are all you guys in the same class? Is this a handout program from the instructor? Are you supposed to work on this without any clues from the instructor? It seems all the questions are stuff that should be covered in class iself.

2 solutions

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OriginalGriff · Answer 1 · 2011-09-05T06:05:00

Solution 1

"my problem is i have toallocte memory for my array using malloc"
Then I would start with declaring a pointer...

C#

int l;
l=(int *)malloc(1000);

Becomes

C#

int* l;
l=(int *)malloc(1000);

After that, we need to know what the error message or similar is...

Posted 5-Sep-11 6:05am

OriginalGriff

Comments

Chuck O'Toole 6-Sep-11 2:24am

his next statement was "int a[l][l]" which will earn him a big compile error on using a variable in this way. I think it was hidden by the fact that, in this font, the lower case letter 'l' is visually similar to the number '1' so the statement looked OK.

Lingaraj from India · Answer 2 · 2011-09-05T20:14:00

#include<stdio.h>
#include <stdlib.h>

int q1, q2, q3, q4;
  void quadrant(int temp1,int temp2)
  {

         if(temp1>=0&&temp2>=0)
        q1++;
      else if(temp1>=0&&temp2<=0)
        q2++;
      else if(temp1<0&&temp2<0)
        q3++;
      else if(temp1<=0&&temp2>=0)
         q4++;

   }

  int main()
  {
  /*int l;
 l=(int *)malloc(1000);*/
  int a[1000][2],c,d,n,i,j,will,b[20][20],k=0;
  char p;
  printf("enter the number of co ordinate");
  scanf("%d",&n);
  for(i=0;i<n;i++)
  for(j=0;j<2;j++)
  scanf("%d",&a[i][j]);
  printf("enter no of operations");
scanf("%d",&will);

while(will>0)
{

p=getchar();
scanf("%c",&p);
switch(p)
{
case 'x':
                scanf("%d %d",&c,&d);
                  for(i=c-1;i<d;i++)
                  a[i][1]=-(a[i][1]);break;
case 'y':
                scanf("%d %d",&c,&d);
                for(i=c-1;i<d;i++)
                a[i][0]=-(a[i][0]);break;
case 'c':       scanf("%d %d",&c,&d);
                for(i=0;i<=n-1;i++)
                {
                 int temp1,temp2;
                 temp1=a[i][0];
                 temp2=a[i][1];

                 quadrant(temp1,temp2);
                }
               b[k][0]=q1;
               b[k][1]=q2 ;
               b[k][2]=q3;
               b[k][3]=q4;

                  k=k+1;
    q1=0;
    q2=0;
    q3=0;
    q4=0;


                  break;
case 'p':   printf(" the co-ordinates are:\n");
               for(i=0;i<n;i++)
               {
                 for(j=0;j<2;j++)
                {
              printf("%d   ",a[i][j]);
                 }
                printf("\n");
                 }
                 break;

default: printf("enter the correct choice\n");break;
}
if(will==1)
for(i=0;i<k;i++)
{
printf("%d %d %d %d\n",b[i][0],b[i][1],b[i][2],b[i][3]);

}
will--;
}
}