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2.00/5 (1 vote)

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C#

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace EvenandOdds
{
    class Program
    {
        static void Main(string[] args)
        {
            List<double> even = new List<double>();
            List<double> odd = new List<double>();

            Console.Write("odd: ");
            Random randomNums = new Random();

            for (int i = 0; i < 25; i++) ;
            {
                odd.Add(randomNums.Next(0,100));

                Console.WriteLine();

            }
             Console.ReadLine();

            }
        }
    }

What do I put in that last WriteLine to show the odd numbers?

Posted 31-Oct-11 9:23am

Member 8349150

Updated 31-Oct-11 9:27am

André Kraak

v3

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Nish Nishant · Answer 1 · 2011-10-31T09:28:00

Solution 1

Well, you do not check if the number is odd. To do that do something like :

C#

bool isOdd = num % 2 != 0;

Use a local variable there and assign the random number to this local. Then you can easily show it using Console.WriteLine. Or access the last item using list[count - 1].

Posted 31-Oct-11 9:28am

Nish Nishant

Updated 31-Oct-11 9:30am

v3

Comments

André Kraak 31-Oct-11 15:31pm

my 5, took me to long to find the MSDN % operator link.

Nish Nishant 31-Oct-11 15:32pm

Yeah, MSDN is not easy to search huh? :-)

Sergey Alexandrovich Kryukov 31-Oct-11 17:24pm

First, one needs to know what is MSDN... My 5 for the answer.
--SA

André Kraak · Answer 2 · 2011-10-31T09:30:00

Solution 2

You need to check for odd numbers, which you can do with the % operator[^].

C#

int Num = 5;

if(Num % 2 == 0)
{
  // It's even

}
else
{
  // It's odd

}

Posted 31-Oct-11 9:30am

André Kraak

Comments

Nish Nishant 31-Oct-11 15:33pm

Voted 5 as well. We posted at the same time I guess.

André Kraak 31-Oct-11 15:35pm

Thanks.

Member 8349150 31-Oct-11 15:41pm

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace EvenandOdds
{
class Program
{
static void Main(string[] args)
{

int random;

List<double> even = new List<double>();
List<double> odd = new List<double>();

Console.Write("odd: ");
Random randomNums = new Random();

for (int randomm = 0; randomm < 25; randomm++)
{
odd.Add(randomNums.Next(0, 100));

bool isOdd = randomm % 2 != 0;

Console.WriteLine(odd[randomm].ToString());
Console.ReadLine();

}
}

}
}

Does not work too well but I tried what you said

Sergey Alexandrovich Kryukov 31-Oct-11 17:25pm

...and you did not explain what's "not too well".
--SA

Sergey Alexandrovich Kryukov 31-Oct-11 17:25pm

Sure, a 5.
--SA

André Kraak 31-Oct-11 17:39pm

Thanks.