How to turn this code to "async mode", because my process frezze when I start a long process standardoutput redirection of DOS like programs.

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How to turn this code to "async mode", because my process frezze when I start a long process standardOutput redirection of DOS like programs.

C#

public void Process_Ex(string fileName, string arguments)
        {
            My problem is here

            var psi = new ProcessStartInfo(fileName, arguments);

            // Set the options.
            psi.UseShellExecute = false;
            psi.ErrorDialog = false;
            psi.CreateNoWindow = true;

            // Specify CodePage Output
            var encoding = Encoding.GetEncoding(850);
            psi.StandardOutputEncoding = encoding;
            psi.StandardErrorEncoding = encoding;

            // Specify redirection.
            psi.RedirectStandardError = true;
            psi.RedirectStandardInput = true;
            psi.RedirectStandardOutput = true;

            // Create process.
            var process = new Process();
            process.EnableRaisingEvents = true;
            process.StartInfo = psi;

            process.Start();
            
            string s = process.StandardOutput.ReadToEnd();
            richTextBox1.Text = s;
            toolStripStatusLabel1.Text = "Runngig Process : " + fileName;
            
            return;
        }

What I have tried:

I'm sory if code like randomly writed.

C#

process.BeginOutputReadLine();
process.WaitForExit();
process.BeginErrorReadLine();
process.BeginOutputReadLine();
process.BeginErrorReadLine();
string otp = process_ErrorDataReceived;
richTextBox1.Text = process_ErrorDataReceived;
StreamReader reader = new StreamReader();
var sortOutput = new StringBuilder("");
process.OutputDataReceived += new
DataReceivedEventHandler(SortOutputHandler);
process.BeginOutputReadLine();
process.OutputDataReceived += p_OutputDataReceived;
private void SortOutputHandler(object sendingProcess, DataReceivedEventArgs
outLine)
{
var sortOutput = new StringBuilder("");

sortOutput.Append(Environment.NewLine + "[" + numOutputLines.ToString() + "]
- " + outLine.Data);
sortOutput.Append(Environment.NewLine + "[" + "] - " + outLine.Data);
richTextBox1.AppendText(sortOutput.ToString());
if (this.InvokeRequired)
this.Invoke(new UpdateLabelDelegate(this.));
richTextBox1.Invoke();
void p_OutputDataReceived(object sender, DataReceivedEventArgs e)
{
string RTB = (e.Data);
richTextBox1.Invoke((Delegate) => richTextBox1.Text = RTB;
richTextBox1.Text += RTB;
Console.Write(e.Data);

Posted 19-Apr-19 9:37am

GSylvain55

Updated 20-Apr-19 17:01pm

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2 solutions

Solution 1

Use a background worker. Update the text box (i.e. UI) from the progress reporting event and / or the completed event which run on the UI thread. Use a concurrent queue and / or pass state objects to the event handlers.

BackgroundWorker Class (System.ComponentModel) | Microsoft Docs[^]

Posted 19-Apr-19 12:49pm

Gerry Schmitz

Comments

GSylvain55 20-Apr-19 0:28am

Yes, I understand. But can you write a symple code to give me a direction. I've been trying for 3 days.
thank you very much !

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GSylvain55 · Accepted Answer · 2019-04-20T17:01:00

I find a other method, it work.
But, I would have liked to know how to do with BackgroundWorker.

C#

public void Process_Ex(string fileName, string arguments)
{

    var psi = new ProcessStartInfo(fileName, arguments);

    // Set the options.
    psi.UseShellExecute = false;
    psi.ErrorDialog = false;
    psi.CreateNoWindow = true;

    // Specify CodePage Output
    var encoding = Encoding.GetEncoding(850);
    psi.StandardOutputEncoding = encoding;
    psi.StandardErrorEncoding = encoding;

    // Specify redirection.
    psi.RedirectStandardError = true;
    psi.RedirectStandardInput = true;
    psi.RedirectStandardOutput = true;

    // babkground worker
    //Process.

    // Create process.
    var process = new Process();
    process.EnableRaisingEvents = true;

    process.StartInfo = psi;

    process.Start();
    process.OutputDataReceived += new
    DataReceivedEventHandler(SortOutputHandler);
    process.BeginOutputReadLine();
    process.BeginErrorReadLine();

    return;
}

void SortOutputHandler(object sender, DataReceivedEventArgs e)
{
    Trace.WriteLine(e.Data);
    this.BeginInvoke(new MethodInvoker(() =>
    {
        richTextBox1.AppendText(Environment.NewLine + e.Data ?? string.Empty);
    }));
}