How to post the select option from combobox into mysql database unsing html/php

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Hi!, i have the code below to populate the combobox from mysql table(location) values, can anyone help me how insert the selected option into mysql database table(customer)using html/php post method....

PHP

//php function to populate combobox


 function location(){

   $database="da_name"
   mysql_connect ("localhost", "root", "pasword");
   @mysql_select_db($database) or die("Unable to select database");
   $query="SELECT state,location FROM location"

   $result = mysql_query ($query);
   echo '<select name="id" value=" ">';
   // printing the list box select command

   while($nt=mysql_fetch_array($result)){//Array or records stored in $nt
   echo "<option value=$nt[location]>$nt[location]</option>";
   /* Option values are added by looping through the array */
   }
   }
   echo "</select>";
// Closing of list box
   ?>

** now I have table (customer with fields -->name, location, contact) please anyone can help how to insert the selected option along with the name & contact fields

*** please help me with the code for data.php & insert.php to complete the application

Posted 23-Feb-12 0:11am

ramen79

Updated 23-Feb-12 0:20am

Syed Salman Raza Zaidi

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graciax8 · Accepted Answer · 2012-02-23T22:31:00

try this one.

PHP

// Form a query to populate the combo-box
$queryitem = "SELECT state, location FROM location"

// Successful query?
if($result = mysql_query($queryitem))  {

  // If there are results returned, prepare combo-box
  if($success = mysql_num_rows($result) > 0) {
    // Start combo-box
    echo "<select name='item'>n";
    echo "<option>-- Select Item --</option>";

    // For each item in the results...
    while ($row = mysql_fetch_array($result))
      // Add a new option to the combo-box
      echo "<option value='$row[location]'>$row[location]</option>n";

    // End the combo-box
    echo "</select>n";

Best Regards,
@iamsupergrasya