that statement doesn't mean anything.

are you sure it doesn't say "Modulate the answer by 1007" ?

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i am getting a number>=0 and that number is answer but probblem states Module the answer by 1007

here is problem:

There are n variables and m requirements. Requirements are represented as (x <= y), which means the x-th variable must be smaller or equal to the y-th variable. Assign nonnegative numbers smaller than 10 to each variable. Please calculate how many different assignments that match all requirements. Two assignments are different if and only if at least one variable is assigned different number in these two assignment. Module the answer by 1007.

Input Format:

First line of the input contains two integers n and m. Then following m lines each containing 2 space-seperated integers x and y, which means a requirement (x <= y).

Output Format:

Output the answer in one line.

Constraints:

0 < n < 14

0 < m < 200

0 <= x, y < n

Sample Input:

6 7

1 3

0 1

2 4

0 4

2 5

3 4

0 2

Sample Output: 1000

EDIT: added more information from a comment below - lewax00

v3

Comments

that statement doesn't mean anything.

are you sure it doesn't say "Modulate the answer by 1007" ?

are you sure it doesn't say "Modulate the answer by 1007" ?

Comments

it is "Module the answer by 1007"

i am getting a number>=0 and that number is answer but probblem states Module the answer by 1007

"Module" is not an English verb. You can't "module" anything.

you can modulate a number: x = x % 1007;

you can modulate a number: x = x % 1007;

Shot in the dark here..but I assume it meant **modulo** not module, in that case that would be the operation used to find the remainder from division, in many languages "%" is used for this, so in your case something along the lines of

That's the best I can offer with what litte information you gave.

`someNumber % 1007`

That's the best I can offer with what litte information you gave.

Comments

thanks.....but it's not modulo.......because i have tried modulo and it's not satisfying the answer

Then I'd recheck the rest of your program, because that's the most sense I can make of it. If you posted more information (for example, your code and the complete problem) we may be able to help your further.

here is problem:

There are n variables and m requirements. Requirements are represented as (x <= y), which means the x-th variable must be smaller or equal to the y-th variable. Assign nonnegative numbers smaller than 10 to each variable. Please calculate how many different assignments that match all requirements. Two assignments are different if and only if at least one variable is assigned different number in these two assignment. Module the answer by 1007.

Input Format:

First line of the input contains two integers n and m.

Then following m lines each containing 2 space-seperated integers x and y, which means a requirement (x <= y).

Output Format:

Output the answer in one line.

Constraints:

0 < n < 14

0 < m < 200

0 <= x, y < n

Sample Input:

6 7

1 3

0 1

2 4

0 4

2 5

3 4

0 2

Sample Output:

1000

There are n variables and m requirements. Requirements are represented as (x <= y), which means the x-th variable must be smaller or equal to the y-th variable. Assign nonnegative numbers smaller than 10 to each variable. Please calculate how many different assignments that match all requirements. Two assignments are different if and only if at least one variable is assigned different number in these two assignment. Module the answer by 1007.

Input Format:

First line of the input contains two integers n and m.

Then following m lines each containing 2 space-seperated integers x and y, which means a requirement (x <= y).

Output Format:

Output the answer in one line.

Constraints:

0 < n < 14

0 < m < 200

0 <= x, y < n

Sample Input:

6 7

1 3

0 1

2 4

0 4

2 5

3 4

0 2

Sample Output:

1000

You need to explain what is Module the answer by 1007, because i found only 19 matches, or may be i didnt understand the problem

Brute force approach (let the computer calculate the problem as stated) for the sample data results in:

Hence, I dare to state that "Module" means**modulo**.

Cheers

Andi

PS: The code (a quick and dense hack to get going):

`count = 25168 % 1007 = 1000`

Hence, I dare to state that "Module" means

Cheers

Andi

PS: The code (a quick and dense hack to get going):

```
static int Loop(int x, List<int> v, Func<bool> check)
{
if (x == 0) return check() ? 1 : 0;
int pos = v.Count() - x;
return Enumerable.Range(0, 10)
.Aggregate(0, (r, i) =>
{ v[pos] = i; return r += Loop(x - 1, v, check); });
}
static void CheckProblem(int n, params Tuple<int, int>[] req)
{
List<int> v = new List<int>(new int[n]);
int count = Loop(n, v, ()=>
req.Aggregate(true, (r, p) => r && v[p.Item1] <= v[p.Item2]));
Console.WriteLine("count = {0} % 1007 = {1}", count, count % 1007);
}
static void Main(string[] args)
{
Func<int, int, Tuple<int, int>> r = (a, b) => new Tuple<int, int>(a, b);
CheckProblem(6, r(1,3), r(0,1), r(2,4), r(0,4), r(2,5), r(3,4), r(0,2));
}
```

v3

Comments

thanks....but this is a sample test case......it must satisfy other test cases also.....

Uups: I did it in C# and not in C/C++/Perl/... Sorry.

But the question about modulo is solved, I think, and you have sample data (count = 25168) to check your solution against.

In C#, you simply need to read in values for n and the requirements pairs and finally pass the data to the CheckProblem(n, reqList) function.

Cheers

Andi

But the question about modulo is solved, I think, and you have sample data (count = 25168) to check your solution against.

In C#, you simply need to read in values for n and the requirements pairs and finally pass the data to the CheckProblem(n, reqList) function.

Cheers

Andi

See my C++ solution#5.

Cheers

Andi

Cheers

Andi

```
#include<stdio.h>
#include<stdlib.h>
typedef struct com
{
int a;
int b;
}com;
int comp(com *a,int m)//this function checks the repeated pair and count them
{
int i=0;
int j=0;
int c=0;
for(j=0;j<m-1;j++)
{
for(i=1;i<=m-1-j;i++)
{
if(a[j].a==a[j+i].a&&a[j].b==a[j+i].b&&a[j].a!=-1&&a[j].b!=-1)
{
c=c+1;
a[i+j].a=-1;
a[i+j].b=-1;
}
}
}
//printf("%d",c);
return c;
}
void main()
{
int n,m;
com *a,*d;
int i;
int c=0,r;
scanf("%d %d",&n,&m);
a=(com *) malloc(sizeof(com)*m);
d=(com *) malloc(sizeof(com)*m);
for(i=0;i<m;i++)
{
scanf("%d %d",&a[i].a,&a[i].b);
d[i].a=a[i].a;
d[i].b=a[i].b;
if(a[i].a<=a[i].b&&a[i].b<n&&a[i].a>=0)
{
c=c+1;
}
}
r=comp(d,m);
c=c-r;//it is the no of distinct pair
printf("%d",1007-(c%1007));//a try for final answer but this does not satisfy other test cases
}
```

Comments

Does this solve your problem or is this a request to help solving it?

Now the C++ version of Solution#3 above:

Output:

Cheers

Andi

```
#include <iostream>
#include <vector>
#include <cassert>
using namespace std;
class Requirements
{
private:
class Req
{
public:
Req(): _x(0), _y(0) {}
Req(int x, int y): _x(x), _y(y) {}
int x() { return _x; }
int y() { return _y; }
private:
int _x;
int _y;
};
vector<Req> _req;
size_t _n;
size_t _m;
public:
Requirements(size_t n, size_t m): _req(), _n(n), _m(m) { }
bool Add(int x, int y)
{
assert(_req.size() < _m);
if (x < 0) return false;
if (y < 0) return false;
if (x >= int(_n)) return false;
if (y >= int(_n)) return false;
if (x >= y) return false;
_req.push_back(Req(x,y));
return true;
}
bool Check(vector<int>& v)
{
assert(v.size() == _n);
for(size_t i = 0; i < _m; ++i)
{
if (v[_req[i].x()] > v[_req[i].y()]) return false;
}
return true;
}
};
class Values
{
private:
vector<int> _v;
Requirements& _req;
public:
Values(size_t n, Requirements& req): _v(n), _req(req) {}
int Loop(int i)
{
if (i == 0) return _req.Check(_v) ? 1 : 0;
int count = 0;
size_t pos = _v.size() - i;
for(int k = 0; k < 10; ++k)
{
_v[pos] = k;
count += Loop(i-1);
}
return count;
}
};
int main()
{
size_t n, m;
cout << "please enter: n m: ";
cin >> n >> m;
Requirements req(n, m);
Values v(n, req);
for(size_t i = 0; i < m; ++i)
{
int a,b;
cout << "please enter req #" << i+1 << " (x <= y): x y: ";
cin >> a >> b;
req.Add(a,b);
}
int count = v.Loop(n);
cout << "count = " << count << " % 1007 = " << (count % 1007) << "\n";
}
```

Output:

`count = 25168 % 1007 = 1000`

Cheers

Andi

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