Compile function pointer on Linux

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Hi,

I am creating one shared library in Linux using Qt and C as programming language. When i compile my code it show me one error like this

expected ‘)’ before ‘*’

/home/arun/Documents/sFlowAnalyzingSampleInC#/sFlowLib/sFlowLib-build-desktop-Qt_4_8_2_in_PATH__System__Release/../sFlowLib/src/sflowtool.c:432: error: expected ‘)’ before ‘*’ token

/home/arun/Documents/sFlowAnalyzingSampleInC#/sFlowLib/sFlowLib-build-desktop-Qt_4_8_2_in_PATH__System__Release/../sFlowLib/src/sflowtool.c:4467: error: expected ‘)’ before ‘managedCallback’

And my code is

C#

void *(  CALLBACK *managedCallback1)(char **);
       void *(  CALLBACK *managedStopCallback)();

C#

void StartCallback( void (* CALLBACK managedCallback(char **)))
{
        managedCallback1=managedCallback;

}

 void StopCallback( void (* CALLBACK managedCallback()))
{
        managedStopCallback=managedCallback;

}

How I can solve this

Posted 18-Jun-12 20:56pm

Arun Kumar K S

Updated 18-Jun-12 21:07pm

v2

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This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Richard MacCutchan · Accepted Answer · 2012-06-18T21:43:00

Solution 1

Should be:

C++

void (CALLBACK *managedCallback1)(char **);

void (CALLBACK *managedStopCallback)();

The extra asterisk before the open parenthesis is incorrect.

Posted 18-Jun-12 21:43pm

Richard MacCutchan

Comments

Arun Kumar K S 19-Jun-12 3:54am

still same problem exist

Richard MacCutchan 19-Jun-12 4:04am

Look at the other block of code posted above, you seem to be adding your indirection operators anywhere at random.

Arun Kumar K S 19-Jun-12 3:58am

This is my running code on Visual studio. Its working perfectly on mu visual studio but not in Linux

Richard MacCutchan 19-Jun-12 4:03am

I find that hard to believe.

Arun Kumar K S 19-Jun-12 6:02am

I compiled it by removing CALLBACK but that not worked wirth my mono application as a callback

Richard MacCutchan 19-Jun-12 7:55am

What is CALLBACK defined as?

Arun Kumar K S 20-Jun-12 6:22am

#define CALLBACK __stdcall
its a calling convetion

Arun Kumar K S 20-Jun-12 6:54am

Thanks to your help I solved it by removing CALLBACK and my running code is

void *( *managedCallback1)(char **);
void *( *managedStopCallback)();

Arun Kumar K S 20-Jun-12 6:57am

My 5 to your valuable support

Richard MacCutchan 20-Jun-12 9:11am

Happy to help & glad you got it solved.

Compile function pointer on Linux

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Compile function pointer on Linux

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