Catching an Exception

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5.00/5 (1 vote)

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Hello. This is my problem:

try<br />{<br />  Application.Run(new Form1());<br />}<br />catch(Exception ex)<br />{<br />  MessageBox.Show(ex.Message);<br />}

In Debug-Mode (F5), if exception is thrown, then it goes to catch block.
In Release-Mode (Ctlr-F5), if exception is thrown, then it shows "unexpected exception" from windows. Catch block is not called.

How can I catch unexpected exception in Release-Mode ?

Thanks.

Posted 13-Aug-09 23:47pm

stancrm

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2 solutions

Solution 2

Eddy is right; and catching exception where Application.Run() is done makes no sense.

Also, to get Application.ThreadException triggered
don't forget this (in Main()):

C#

Application.SetUnhandledExceptionMode(
    UnhandledExceptionMode.CatchException);

ThreadException handler should be set up like this:

C#

Application.ThreadException += (sender, args) => {
    MessageBox.Show(string.Format(
            "{0}:\n\n{1}", args.Exception.GetType().Name, 
            args.Exception.Message),
        string.Format(
            " {0}: Error", ProductName),
        MessageBoxButtons.OK, MessageBoxIcon.Error);
}; //ThreadException

Posted 23-Dec-10 9:23am

Sergey Alexandrovich Kryukov

Comments

Dalek Dave 23-Dec-10 20:14pm

Good Call.

Espen Harlinn 26-Feb-11 11:09am

Good reply - a 5

Sergey Alexandrovich Kryukov 26-Feb-11 19:19pm

Thank you.
--SA

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Eddy Vluggen · Accepted Answer · 2009-08-14T00:07:00

There's a special event that gets triggered whenever there's an unhandled exception. Your application could subscribe to the Application.ThreadException[^]-event.

Something like this (adapted from the MSDN-example, not tested);

{<br />// Add the event handler for handling UI thread exceptions to the event.<br />    Application.ThreadException += new ThreadExceptionEventHandler(MyErrorHandler);<br /><br />// Set the unhandled exception mode to force all Windows Forms errors <br />// to go through our handler.<br />    Application.SetUnhandledExceptionMode(UnhandledExceptionMode.CatchException);<br />    Application.Run(new Form1());<br />}<br /><br />private static void MyErrorHandler(object sender, ThreadExceptionEventArgs t)<br />{<br />    ShowMessage(t.ToString());<br />}