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Hi guys..... with this codes below... i successfully encryt text but my problem is... i can't create a vice versa of this.... i mean a "DECRYPTER"... Please Help...... here's my code....

  Public Function pwdMd5Hash(ByVal String2Hash As String) As String
            Dim MD5Hasher As New System.Security.Cryptography.MD5CryptoServiceProvider()
            Dim oEncoder As New System.Text.ASCIIEncoding()
            Dim bytes As Byte() = oEncoder.GetBytes(String2Hash)
            Dim myHash As Byte() = MD5Hasher.ComputeHash(bytes)
            Dim myCapacity As Integer = 7
            Dim sb As System.Text.StringBuilder = New System.Text.StringBuilder(myCapacity)
            Dim I As Integer
            For I = 0 To myHash.Length - 1
                sb.Append(BitConverter.ToString(myHash, I, 1))
            Next I
            Return sb.ToString().TrimEnd(New Char() {" "c})
        Catch ex As Exception
            Return "0"
        End Try
Posted 22-Jul-12 15:16pm
Updated 22-Jul-12 15:22pm
Wes Aday104.2K
Wes Aday 22-Jul-12 21:22pm
You do know that hashes are one way don't you?
iamsupergrasya 23-Jul-12 0:04am
i use a function in a encrypter and decrypter in one. just sharing.
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Solution 1

As Wes said, a hash only goes one way. You can't turn a hash back in to the starting string.
Of course, a 5.
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Solution 2

Considering that MD5 is not an encryption algorithm, but is in fact a hash function (and a broken one at that), no there is no such thing as a decryptor for MD5.
Of course, a 5.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

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