How to define byte array in C/C++?

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i have to define byte array in C/C++
I searched net and found various examples,so confused which one is correct:-
Out of these which one is correct?

C++

unsigned char bytes[]=0x43,0x4d,0x30,0x30,0x0f,0x0D};

const char data3[]={0x43,0x4d,0x30,0x30,0xf0,0x0D};

char data[4]="CM00";

Posted 14-Sep-12 18:59pm

Tarun Batra

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Sergey Alexandrovich Kryukov 15-Sep-12 1:48am

If you have a compiler, you can easily figure this out. If this is some kind stupid interview/test question, this is the abuse(, too :-)).
--SA

Mohibur Rashid 15-Sep-12 3:22am

First of all your code is incorrect. secondly there is few issue you will have learn at the beginning of c programming. I believe you are still beginner. you better study more

3 solutions

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CPallini · Answer 1 · 2014-12-02T03:00:00

Solution 3

All of them are valid (of course, in the first one, the open curly brace is missing).

Posted 2-Dec-14 3:00am

CPallini

Comments

Richard Deeming 2-Dec-14 9:27am

This is a question from September 2012.

CPallini 2-Dec-14 11:35am

OK, it took me a while to answer, so?
:-D

Richard MacCutchan · Answer 2 · 2012-09-15T00:01:00

Solution 1

See fundamental types[^] and subscripts[^].

Posted 15-Sep-12 0:01am

Richard MacCutchan

Member 11254928 · Answer 3 · 2014-12-02T02:01:00

Solution 2

byte test[5]={0xb4,0xaf,0x98,0x1a,0xb5};

Posted 2-Dec-14 2:01am

Member 11254928

Comments

CPallini 2-Dec-14 8:58am

This is plain wrong, C/C++ have no 'byte' as builtin type.