Converting uString to Const char *

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Hola guys,

I wanna ask something about converting variable.
The story goes when I have :

C++

uString text;

which I need he to be convert as const char *.
I've tried the same way how to convert std::string to const char, but it didn't work.

C++

std::string str;
char * writable = new char[str.size() + 1];
std::copy(str.begin(), str.end(), writable);
writable[str.size()] = '\0'; 

delete[] writable;
                        // NOOTTTT WORRRKKKK FOR MEE!!!!//////

Anybody knows how to do it?

Thanks

Posted 28-Oct-12 22:21pm

satrio_budidharmawan

Updated 29-Oct-12 0:39am

TorstenH.

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TorstenH. 29-Oct-12 6:40am

I removed the Java Tag - don't know what this has to do with java.

pasztorpisti 29-Oct-12 7:17am

Maybe it uses the ICU library on which java's unicode support builds but ICU has an UString and not an uString. We don't exactly know what is this uString so we can not know how to handle it... I'm afraid the poster has no clear understanding of text encoding.

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enhzflep · Answer 1 · 2012-10-28T22:57:00

I can't be sure, but it sounds like you have a function that takes a const char* as an input, and all you have is a std::string. If that's the case, you can forget about the const part for now - that's there to indicate to you and be made enforceable by the compiler that no changes will happen to that variable during the function. - This will actively prevent writing data to a var that's a reference.

But, getting back to the issue at hand, how to convert a std::string into something more useful.

How about just this plain and simple 1 liner?

char *writeable = str.c_str();

You can find the docs here: http://www.cplusplus.com/reference/string/string/c_str/[^]

Note specifically, you (a) don't have to allocate the memory yourself (b) you don't have to free it yourself (c) you shouldn't try to modify it - it's a const char*

Converting uString to Const char *

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Converting uString to Const char *

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