FileInputStream

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Hi all,

can anyone please tell me what does the marked lines do ? I mean, what is their functionality respective of the code below.

public static void main(String args[])
{
VRJDBCPropXmlHandler handler = new VRJDBCPropXmlHandler();
try
{
FileInputStream fin = new FileInputStream(args[1]); --------------> ???
handler.execute(fin);
}
catch(FileNotFoundException fnfe)
{
fnfe.printStackTrace();

}
catch(Exception e)
{
e.printStackTrace();
}
}

public void execute(InputStream is) throws Exception {
SAXParser parser = spf_.newSAXParser();
try
{
parser.parse(is, this); ----------------------> ???
}
catch (Exception ex)
{.....
}

Posted 22-Dec-09 5:34am

jazy_smith

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Rick Shaub · Answer 1 · 2009-12-22T06:13:00

This line opens a file for reading as a stream,using args[1] as the path. The variable "args" contain the command line arguments.

FileInputStream fin = new FileInputStream(args[1]);

This line parses the file as XML using the containing class as a DefaultHandler DefaultHandler[^]

parser.parse(is, this);

Also see: http://java.sun.com/j2se/1.4.2/docs/api/javax/xml/parsers/SAXParser.html#parse(java.io.InputStream,%20org.xml.sax.HandlerBase)[^]

jazy_smith · Answer 2 · 2009-12-22T06:28:00

Solution 2

@rick: hi rick. FileInputStream(args[1]) why is there args[1] parameter ? How can it be used over here? can you please explain in detail ?

Posted 22-Dec-09 6:28am

jazy_smith

Rick Shaub · Answer 3 · 2009-12-22T07:10:00

Solution 3

Jazzy, use the "messages" are for additional questions and dialog, as the "answers" section is not threaded. See my original answer for clarification on your question.

Posted 22-Dec-09 7:10am

Rick Shaub

ARUN482 · Answer 4 · 2010-01-21T23:25:00

FileInputStream fin = new FileInputStream(args[1]);

The above line opens a file in read mode and the value is retrieved as a stream. args[1] is the filepath. Args[1] is the value given(next to class name) while running the program.

parser.parse(is, this);