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I wanna overload '+' operator and add the elements of two series by using vector. But anytime I run the code , the first elements of my vectors get 'inf' . I can't understand why I get this error. I checked my code several time whether I had done mistake while filling vector but I coulnt find anything to correct. Anyone has any idea about this mistake? here is the compiled code and results ->[^]

#include <cstdlib>
#include <iostream>
#include <vector>
#include <cmath>

using namespace std;

class Overload {
    Overload operator+(Overload &) ;
    void SetK(int k);
    int GetK() const;
    void SetVect(vector<double> vect);
    vector<double> GetVect() const;
    vector<double> vect ;
    int k ;


int main(int argc, char** argv) {
    Overload a,b(10),c(10) ;
    a= b+c ;
    cout <<"\nAdded :\n" ;
    for(unsigned int i=0;i<a.GetVect().size(); ++i)
    cout <<"Res : " << a.GetVect()[i] << endl ;   
    cout << "first element : "<< a.GetVect()[0] << endl ; 
    return 0;

Overload::Overload() {
    k=10 ;
    cout << "\nFrist Started\n" ;
    for(unsigned int i=0;i<k ; ++i){
        double res = 1/pow(i,2) ;
        cout << vect[i] << " " ;
    cout << "VEctor size : " << vect.size() << endl ;
    cout <<"\nfirst ended\n"<< endl ;

Overload::Overload(int k) {
    double res=0 ;
    cout << "\nsecond started : \n" ;
    for(unsigned int i=0;i<k ; ++i){
        res = 1/pow(i,2) ;
        cout << vect[i] << " " ;
    cout << "\nsecond ended : \n" ;

Overload Overload::operator+(Overload &a){
    double res=0 ;
    Overload x ;
    for(unsigned int i=0 ;i<vect.size();i++) {
        res = vect[i] + a.vect[i];
        x.vect.push_back(res) ;
    return x ;

void Overload::SetK(int k) {
    this->k = k;

int Overload::GetK() const {
    return k;

void Overload::SetVect(vector<double> vect) {
    this->vect = vect;

vector<double> Overload::GetVect() const {
    return vect;
Updated 9-Nov-12 21:52pm
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1 solution

Both in ::Overload() and ::Overload(int k) the first iteration of the for loop calculates 1/pow(i,2) for i=0. Which means you end up dividing by zero which is represented by the Inf value.

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