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when i trace the code im getting 1,3,5,7 for the answer but the compiler prints 1,3,6,10
im having trouble understanding how this happens could anyone explain

int [] a= new int[5];  // create array
for (int i =1; i<=4; i++)    
  System.out.print(a[i]+" ");
Posted 10-Nov-12 12:32pm
Updated 10-Nov-12 13:23pm
Nelek 10-Nov-12 18:44pm
What I can not understand is where you get 1,3,5,7. The result of this code is what the compiler prints.

1 solution

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Solution 1

when i trace the code

You debug it. While debugging you figure several operations in one line:

for (int i =1; i<=4; i++)    
  System.out.print(a[i]+" ");

should be

for (int i =1; i<=4; i++)    
  int iNumber = a[i-1]; // get number of previous field
  iNumber += i; // add counter
  a[i]=iNumber; // place result
  System.out.print(a[i]+" ");

This way you can figure every step and see that the output if this is "1 3 6 10".

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

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