Click here to Skip to main content
12,999,081 members (47,945 online)
Rate this:
Please Sign up or sign in to vote.
See more:

Can any one please tell me how to find all words from a particular directory which contains a,e,i,o,u in order.

Ex abstancious. Here 'a' followed by 'a' followed by 'i' followed by 'o' followed by 'u'. Vowels never repeated.

I have cat /home/user1/tmp/* | grep [aeiou]

But it's not displaying my expected answer.

Please help.

Thanks in advance.
Posted 20-Nov-12 18:23pm

1 solution

Rate this: bad
Please Sign up or sign in to vote.

Solution 1

Your regular expression is just looking for any single vowel. You want something more like "^[^aeiou]*a[^aeiou]*e[^aeiou]*i[^aeiou]*o[^aeiou]*u[^aeiou]*$" I think (assuming it must have all of them). This one searches for zero or more consonants, a, zero or more consonants, e, etc.
srmohanr 21-Nov-12 5:12am
Please refine the answer more. Because even I am getting the output 'unfacetiousness'. But this is not my scenario.

Please help
lewax00 21-Nov-12 10:06am
I updated it to match only whole lines. You should take the time to learn regular expressions, they can be very useful.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

  Print Answers RSS
Top Experts
Last 24hrsThis month

Advertise | Privacy | Mobile
Web02 | 2.8.170622.1 | Last Updated 21 Nov 2012
Copyright © CodeProject, 1999-2017
All Rights Reserved. Terms of Service
Layout: fixed | fluid

CodeProject, 503-250 Ferrand Drive Toronto Ontario, M3C 3G8 Canada +1 416-849-8900 x 100