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Write JS code for this...

Member 14710674 asked:

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Write an if....else statement that:

-prints "even" if the number is an even number
-prints "odd" if the number is an odd number

(use the % operator to determine if the number is odd or even)

What I have tried:

* Programming Quiz: Even or Odd (3-2)
* Write an if...else statement that prints `even` if the
* number is even and prints `odd` if the number is odd.
* Note - make sure to print only the string "even" or the string "odd"

// change the value of `number` to test your if...else statement

var number = 2;

if (number % 2 = 0 ); {console.log("even");} else {console.log("odd");

Tags: Javascript


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