Separate values of a dictionary in a for loop

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How can i separate the values of my dictionary in the for loop like this, with .items() does anyone know how to do that? or is there a better way?

this wil now give me:

[2, 0]
[3, 0]
4

i would like to print the 2 and the 0 etc. separate from each other.

What I have tried:

Python

producten = {'appel': [2, 0], "banaan": [3, 0], 'peer': 4}


for product, prijs in producten.items():
    print(prijs[1])

Posted 22-Sep-20 11:49am

Member 13554627

Updated 22-Sep-20 22:34pm

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Sandeep Mewara · Answer 1 · 2020-09-22T19:00:00

You can do Unzip (reverse of zip) tuples using a * and zip.

Example:

Python

producten = {'appel': [2, 0], "banaan": [3, 0], 'peer': 4}
  
keys, values = zip(*producten.items()) 
  
print ("keys : ", str(keys)) 
print ("values : ", str(values)) 

#output
('keys : ', "('appel', 'banaan', 'peer')")
('values : ', '([2, 0], [3, 0], 4)')

Refer: Using * and zip to 'unzip'[^]

Richard MacCutchan · Answer 2 · 2020-09-22T22:35:00

Try this:

Python

producten = {'appel': [2, 0], "banaan": [3, 0], 'peer': 4}
for product, prijs in producten.items():
    if type(prijs) is list:
        for item in prijs:
            print(item)
    else:
        print(prijs)

It is probably not the exact answer you are looking for but is shows you how to separate the values.

Separate values of a dictionary in a for loop

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