JAVA as IF, is my answer correct?

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Question=

You are required to analyze the performance for Principles of Computer Programming subject
containing 135 students. Your program will prompt for final marks of each student, accumulate
the total and calculate the average. Display the average mark and the grade obtained

<pre lang="text">

Design a pseudocode and write a full java program to provide
the solution.

Table 2: Grade Category based on Average Mark
Average mark range // Grade Category
Below 50 // Low
50 to 79 // Good
80 and above // Excellent

What I have tried:

Java

import java.util.*;
public class Mark {
    public Mark () {
    }
    
    public static void main(String args[]) {
      Scanner input = new Scanner (System.in);
      int avgMark;
      
      System.out.println(" Your Score: ");
      avgMark = input.nextInt();
      
      if(avgMark >= 80)
      {
          System.out.println("Grade: Excellent");
      }
      
      else if (avgMark >= 50 && avgMark <= 79) {
          System.out.println(" Grade: Good ");
      }
      
      else if (avgMark <= 50) {
          System.out.println(" Grade: Low ");
      }
    }
}

<pre lang="java"><pre lang="java">

Posted 2-Nov-20 18:36pm

tomatomoa

Updated 2-Nov-20 20:36pm

CPallini

v2

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CPallini · Answer 1 · 2020-11-02T20:27:00

Solution 1

Yes, your if clause is correct, but contains redundant checks. Igt can be replaced by the following code

Java

if(avgMark >= 80)
     {
         System.out.println("Grade: Excellent");
     }
     else if (avgMark >= 50 )
     {
         System.out.println(" Grade: Good ");
     }
     else
     {
         System.out.println(" Grade: Low ");
     }

Posted 2-Nov-20 20:27pm

CPallini

Comments

tomatomoa 3-Nov-20 4:26am

thanks, but just now my friends said that it included loop and we must calculate and display the avgMark but I'm confuse right now. do you have any idea?

OriginalGriff · Answer 2 · 2020-11-02T20:37:00

Solution 2

In addition to what CPallini has said, I'd change it a little to use a function to return the grade, and print that:

Java

public static String getGrade(int score) {
   if(score >= 80) {
      return "Excellent";
   }
   else if (score >= 50 ) {
      return "Good";
   }
   return "Low");
}

And then use that to print the result:

Java

System.out.println("Grade: " + getGrade(studentScore));

It's then a lot easier to move on the the second part of your task and repeat the scoring for the remaining 134 students, knowing that the "grading" part of the task is done and working.

Posted 2-Nov-20 20:37pm

OriginalGriff

Comments

tomatomoa 3-Nov-20 4:28am

thanks, the last part is useful, my friend said we must calculate and display the avgMark but I'm confused by it right now. do you have any idea?

OriginalGriff 3-Nov-20 5:00am

Well, you know how to calculate an average:

avg = Sum(marks) / NumberOf(marks)

e.g.:

avg = (1 + 5 + 7) / 3

So what part is giving you difficulties?
Where are you stuck?
What have you tried?
What help do you need?

tomatomoa 3-Nov-20 5:41am

I couldn't catch up thus fast. So based on my Rubik Question, is this like this?

avgMark = studentMark / 100

I'm sorry,

OriginalGriff 3-Nov-20 6:03am

No, think about it: you need to add up all the entered marks and count them. Then when you have the total of all marks, you can divide that by the count.

So start with a variable to hold the total, and add to it each time you go round the loop entering new values. Count it as well, then after that loop is finished you can work out the average.

Think about it - that's how you would do it manually: you'd get a calculator, and add each value to it one by one, then divide the total afterwards.

tomatomoa 3-Nov-20 8:46am

i tried but idk anymore,, this is my final answer of the question, there are many mistake right ; - ;

import java.util.*;
public class Mark {
public Mark () {
}

public static void main(String args[]) {
for(int i = 135; i < n; i++)

String grade;
int avgMark;
int finalMark;

Scanner input = new Scanner (System.in);

avgMark = finalMark / 135

System.out.println(" pls enter your final mark: ");
finalMark = input.nextInt();

if(avgMark >= 80)
{
System.out.println("Grade: Excellent");
}

else if (avgMark >= 50 && avgMark <= 79) {
System.out.println(" Grade: Good ");
}

else if (avgMark <= 50) {
System.out.println(" Grade: Low ");
}

}
}

OriginalGriff 3-Nov-20 8:57am

So you've totally ignored everything we have told you so far?

No point in trying to help you further then, is there?

tomatomoa 3-Nov-20 9:01am

It's not like I ignored, but I just don't know how even after numerous explanations,, I just can't understand it. sorry if I sound dumb , yet tq

OriginalGriff 3-Nov-20 9:21am

If you haven't ignored what we said, where is the evidence of that in your code? Because the latest code fragment you show is almost identical to the original - it shows no input from us, and - to be honest - no real sign of thought in what has changed ... so where is the point in us spending our valuable time typing when you ignore what we tell you?

tomatomoa 3-Nov-20 9:26am

again, im truly sorry

OriginalGriff 3-Nov-20 9:38am

"Sorry don't cut bait."

So start by reading what we said, and using it. Show us you are paying attention and trying to do your homework yourself.

JAVA as IF, is my answer correct?

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JAVA as IF, is my answer correct?

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