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```Generate a 3x3 identity array. Then, convert the identity array into the 2-d float array as shown in the desired output. Must use the np.eye() function.

Hint: use arithmetic operations.

Desired output:
[[1.8 0.9 0.9]
[0.9 1.8 0.9]
[0.9 0.9 1.8]]

What I have tried:

<pre># 1. import numpy
import numpy as np

# 2. create a 3x3 identity array
x = np.eye(3)

# 3. convert the identity array into the desired array
array = np.array(x)

# 4. print the desired array
print(array)```
Posted
Updated 8-Dec-20 21:01pm

## Solution 1

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## Solution 2

Once you've called the `np.eye()` method, you might iterate on the array and simply add the appropriate constant, based on the current value of the item (that is `1` on the diagonal, `0` elsewhere).