Extracting data from mysql to HTML table

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I am having trouble trying to extract the data from mysql, I have tried every tutorial but still have problems. It only seems to show and loop the title and not the data. Not sure where the problem lies

<html>
  <head></head>
  <body>
    <?php
      $con = mysqli_connect("localhost","root","","oatdistribution");
      $tabsql = "SELECT 'Name', 'LivingCondition', 'OatType', 'NoOfOat', 'Status' FROM OatDis"; 
      $data = mysqli_query($con,$tabsql);
      $total = mysqli_num_rows($data);
      if($total > 0){
        while($row = mysqli_fetch_assoc($data)){
          echo $row['Name']."<br>";
        }
      }
    ?>
  </body>
</html>

What I have tried:

I have tried multiple types of tutorial online and yet still the same

Posted 23-Mar-21 3:27am

Allysha April

Updated 23-Mar-21 4:58am

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Richard MacCutchan 23-Mar-21 9:48am

How many rows did the original query return?

Allysha April 23-Mar-21 10:53am

it has extactly the same amount of rows that my data has which is 12

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Richard Deeming · Answer 1 · 2021-03-23T04:58:00

Solution 1

Quote:

SQL

SELECT 'Name', 'LivingCondition', 'OatType', 'NoOfOat', 'Status' FROM OatDis

Your query isn't selecting any data from the table. Instead, it's returning a set of literal strings for each row in your table.

I suspect you're trying to quote the column names. To do that, you need to use back-ticks, not single quotes:

SQL

SELECT `Name`, `LivingCondition`, `OatType`, `NoOfOat`, `Status` FROM OatDis

Posted 23-Mar-21 4:58am

Richard Deeming

Comments

Allysha April 23-Mar-21 11:02am

Fatal error: Uncaught TypeError: mysqli_num_rows(): Argument #1 ($result) must be of type mysqli_result, bool given in C:\xampp\htdocs\PieChart\index.php:8 Stack trace: #0 C:\xampp\htdocs\PieChart\index.php(8): mysqli_num_rows(false) #1 {main} thrown in C:\xampp\htdocs\PieChart\index.php on line 8

this was what came up after changing that

Richard Deeming 23-Mar-21 11:04am

Which simply means there was an error executing the query, which you didn't check for.

Most likely a typo in one of the column names.

Try executing the query directly in workbench to see what the error is.

Allysha April 23-Mar-21 11:08am

thank you so much, it was one of the column names. it took me literally hours to debug