How do I get to know the double 66 in randomly generated number to certain lenth

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I have generated the number between 1 to 6 using the randint() but now I want to know how many times the 66 are generated.

Is list needed to be used. Just dont know how to start checking the number.

What I have tried:

from random import *
trial = randint(1, 6)
print(trial)
counter = 0

last_dice = randint(1, 6)
print(last_dice, end='')

for i in range(trial-1):
    new_dice = randint(1, 6)
    print(new_dice, end='')
    if last_dice == 6 and new_dice == 6:
        last_dice = new_dice
        counter += 1

print()
print(counter)

Posted 29-Apr-21 8:20am

Francis Sadiq

Updated 30-Apr-21 1:45am

v2

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3 solutions

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OriginalGriff · Answer 1 · 2021-04-29T08:27:00

If all you are looking for is "how many double sixes are thrown?" then it's pretty simple - you don't have to "remember" all the throws at all, so no list is needed.

Instead, think how you would do it manually with one die.
You'd have an area on the paper for marking each time you got a double six, and you'd remember if the last throw was a six.
Each time you threw, you'd check if it was a six.
If it wasn't, ignore it.
If it was, you'd check if the last one was and increase your "double sixes" count by one.
Then you'd throw again for the next one and repeat until you'd had enough.

So in code you want to do exactly the same thing!

Make sense?

If you are having problems getting started at all, then this may help: How to Write Code to Solve a Problem, A Beginner's Guide[^]

Patrice T · Answer 2 · 2021-04-29T11:12:00

Quote:
I have generated the number between 1 to 6 using the randint() but now I want to know how many times the 66 are generated.

Think about the problem, what do you need to solve the problem by hand?
You do,'t need to keep a list of all dice drawing, all you need is to keep track of last dice.

Python

draw NewDice
If LastDice is 6 and NewDice is 6 then it is a 66
LastDice takes the value of NewDice
and Loop

[Update]
Try this change

Python

for i in range(trial-1):
    new_dice = randint(1, 6)
    print(new_dice, end='')
    if last_dice == 6 and new_dice == 6:
        counter += 1
    last_dice = new_dice

print()
print(counter)

Advice: try to draw more than 6 dices, at least for testing purpose. 36 draw of dice gets a reasonable odd to get a couple of 66.
[Update]

Quote:
I increased the no of draws to 100 and 666 are also being counted as 2 in counter....

When you encounter a 66, After increment counter, change the new_dice to another value to make sure it will not be used again.

Richard MacCutchan · Answer 3 · 2021-04-30T01:45:00

Solution 3

You are making this more complicated than necessary. All you need is to throw two dice and check the values:

Python

for i in range(trial): # the value of trial will need to be fairly large to ensure a good distribution.
    die1 = randint(1, 6)
    die2 = randint(1, 6)
    if die1 == 6 and die2 == 6:
        counter += 1

Posted 30-Apr-21 1:45am

Richard MacCutchan

Comments

Patrice T 30-Apr-21 10:18am

I think the question is for using only 1 dice.

Richard MacCutchan 30-Apr-21 11:10am

That is not what the question says.

Patrice T 30-Apr-21 11:31am

In first version of question, OP was building a list of draws, then scanning the list (with i and i+1) in search of consecutive 66.
That is pretty close to using 1 dice only.

Richard MacCutchan 30-Apr-21 11:35am

But I was answering this question, which specifically asks for the number of double sixes in a set of throws.

Patrice T 30-Apr-21 11:43am

Read again the title: "How do I get to know the double 66 in randomly generated number to certain lenth"

Richard MacCutchan 30-Apr-21 12:03pm

Yes, and that is what I have answered. You have a different interpretation of what "double 6" means.

Francis Sadiq 30-Apr-21 12:52pm

guys.. I have actually found the solution and thank you both of your contributions.

Francis Sadiq 30-Apr-21 12:53pm

Thanks bro.... but please be gentle towards each other.

Patrice T 30-Apr-21 13:09pm

:) no problem.
We are exchanging arguments because we have different opinions.

Richard MacCutchan 30-Apr-21 13:54pm

The world would be a boring place if we all agreed on everything.

Patrice T 30-Apr-21 13:57pm

:)

Richard MacCutchan 30-Apr-21 13:53pm

Always. And thank you for the feedback.

CPallini 30-Apr-21 10:57am

"You are making this more complicated than necessary"
You are oversimplifying, however.

Richard MacCutchan 30-Apr-21 11:11am

Exactly what I meant to do.

CPallini 30-Apr-21 13:43pm

:-D
Have my 5.

Richard MacCutchan 30-Apr-21 13:55pm

Thank you.

How do I get to know the double 66 in randomly generated number to certain lenth

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