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the code below outputs:
Sample Input
10 4 | -
10 is the number of interval
4 is the width of an interval
/ is the major mark
* is the minor mark
Sample Output

I want to add another loop that when you type 'n' as the major mark
the output would be:
Sample Input
3 2 n x
Sample Output

'n' value are numbers from 0, 1, 2, 3... and so on.

What I have tried:

#include <iostream>
using namespace std;
int main()
    int a, b;
    char c, d;
    cin >> a >> b >> c >> d;

    for (int row = 1; row <= a; row++ ){
        cout << c;
        for (int cols = 1; cols <= b; cols++){
            cout << d;
    cout << c;
Updated 22-Sep-21 22:19pm
Richard MacCutchan 23-Sep-21 6:58am
Just check if c is a number when it is input. If so use its values rather than the single character.

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Best is to use the debugger when the code doesnt work as expected. Find some debugger tutorial to kickstart and get some insights.

In C loops are from 0 to less the end. That would change your code like this:
for (int row = 0; row < a; row++ ){
        cout << c;
        for (int cols = 0; cols < b; cols++){
            cout << d;
I would use better names for the vars and chars like for loops

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